Ask question

Ask question

All categories

2 years ago

14

you play games where you score -6 points on the first turn and on each of the next 3 turns. what is your score after those 4 tur

ns

1 answer:

dybincka [34]2 years ago

8 0

I believe the answer is -24

You might be interested in

Simplify. Your answer should contain only positive exponents.

saveliy_v [14]

Answer:

Step-by-step explanation:

7.

2y² * 3x = 6xy²

8.

4v³ * vu²

$= 4 \times 1 \times (v^{3+1})( u^2)$

= 4v⁴u²

9.

4a³b² * 3a⁻⁴b⁻³

$= 4 \times 3 \times a^{(3+(-4))} \times b ^{(2+(-3))}$

= 12a⁻¹b⁻¹

$= \dfrac{1}{12ab}$

10.

x²y⁻⁴ * x³y²

$= x^{2+3}y^{(-4)+2}$

$= x^{5}y^{-2}$

$= x^{5} \times \dfrac{1}{y^{2}}$

11.

(x²)⁰ = 1

12.

(2x²)⁻⁴

$= (2^{-4} \times x^2^{(-4)})$

$= \dfrac{1}{16x^8}$

6 0

2 years ago

Which is the definition of a ray?

shutvik [7]

The correct answer is (A)!

6 0

2 years ago

How are the properties of reflection used to<br> transform a figure?

Lunna [17]

Answer:When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed). ... Remember that each point of a reflected image is the same distance from the line of reflection as the corresponding point of the original figure.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

10. simplify the rational expression by rationalizing the denominator.( 1 point ) 4√150/√189x

ddd [48]

Rationalizing the denominator, simply means "getting rid of that pesky root at the bottom", and we do so by simply multiplying it by something to take it out, of course, we multiply the bottom, we have to also multiply the top,

$\bf \cfrac{4\sqrt{150}}{\sqrt{189x}}\cdot \cfrac{\sqrt{189x}}{\sqrt{189x}}\implies \cfrac{4\sqrt{150}\sqrt{189x}}{(\sqrt{189x})^2}\implies \cfrac{4\sqrt{(150)({189x})}}{189x}$

$\bf \cfrac{4\sqrt{28350x}}{189x}\qquad 
\begin{cases}
28350=2\cdot 3\cdot 3\cdot 3\cdot 3\cdot 5\cdot 5\cdot 7\\
\qquad 2\cdot 3^2\cdot 3^2\cdot 5^2\cdot 7\\
\qquad 2\cdot (3^2)^2\cdot 5^2\cdot 7\\
\qquad 2\cdot (3^2\cdot 5)^2\cdot 7\\
\qquad 2\cdot (45)^2\cdot 7\\
\qquad 14\cdot 45^2
\end{cases}\implies \cfrac{4\sqrt{14\cdot 45^2}}{189x}
\\\\\\
\cfrac{4\cdot 45\sqrt{14}}{189}\implies \cfrac{180\sqrt{14}}{189x}\implies \cfrac{20\sqrt{14}}{21x}$

4 0

2 years ago

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

2 years ago