Here, The function: y = -x² + 4
Input values would be x coordinates & output values would be y.

When, x = 1, y = (-1)² + 4 = 1 + 4 = 5
x = 2, y = (-2)² + 4 = 4 + 4 = 8
x = 3, y = (-3)² + 4 = 9 + 4 = 13

In short, Your Three input values are: 1, 2, 3
Three Output values are: 5, 8, 13

Hope this helps!

4 0

3 years ago

Find the difference quotient off, that is, find fly+h)-f(x) h h#0, for the following function. Be sure to simplify. f(x) = x^2 -

Sloan [31]

The difference quotient for the function f(x) is $h+2x-7$

Given :

Difference quotient formula

$\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}$

Given function $f(x) = x^2 - 7x + 8$

find the difference quotient using the formula

first we find out f(x+h) using given f(x)

replace x with x+h

$f(x) = x^2 - 7x + 8 \\f(x+h)=\mathrm{ }\left(x+h\right)^2-7\left(x+h\right)+8\\Expand \; and \; simplify\\f(x+h)=x^2+2xh+h^2-7\left(x+h\right)+8\\f(x+h)=x^2+2xh+h^2-7x-7h+8$

Now replace it in our formula and also replace f(x)

$\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}\\ \frac{x^2+2xh+h^2-7x-7h+8-(x^2 - 7x + 8)}{h} \\\frac{x^2+2xh+h^2-7x-7h+8-x^2 + 7x - 8}{h} \\\\\frac{h^2+2xh-7h}{h}\\factor \; out \; h\\\frac{h\left(h+2x-7\right)}{h}\\h+2x-7$

Learn more :brainly.com/question/23630564

3 0

3 years ago