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atroni [7]
3 years ago
13

What is the surface area of this triangular prism

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:

180 ft^2

<em>Note: ft^2 represents ft squared</em>

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What is 155.43 rounded to the nearest whole number ?
xxMikexx [17]
155;
rounding to the nearest whole number basically means rounding the decimals so they disappear e.g. 11.5 would round up to 12 because 5+ rounds upwards and below 4 rounds down so say it was 15.34 it would round down so it would be 15.
I hope this helps ;)
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3 years ago
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PLEASE HELP!! WILL MARK BRAINLIEST AND THANK YOU!!!
Semmy [17]

Answer:

The answer is c because you would plug in -2 for x and -6 for y

Step-by-step explanation:

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Which number is a prime number ? <br><br> A. 133<br><br> B. 143<br><br> C. 153<br><br> D. 163
expeople1 [14]

Answer:

A.  133

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3 years ago
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Which of the following shows the extraneous solution(s) to the logarithmic equation? log4 (x) + log4(x - 3) = log4 (-7x + 21)
Salsk061 [2.6K]
First join the log4 on the left:

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Then x = -7, works: -7*(-10)=70 = -7*(-7)+21

x=-3, 18 = 42, does not work

x=3 0=0 works,

However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.

Now x=3 gives log4(0) on the left and right, which does not exist.

So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
 
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3 years ago
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Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
kow [346]

If the perimeter is 9 inches, each side is 3 inches.

The height of an equilateral triangle splits the triangle in two right sub-triangles: for example, consider a triangle ABC and the height AH starting from A, perpendicular to BC.

The triangle AHC is a right triangle, whose legs are AH and HC, and whose hypotenuse is AC.

AH is half the side, and AC is a side. So, we can use the Pythagorean theorem to find the height:

AH = \sqrt{AC^2-AH^2}=\sqrt{l^2-\dfrac{l^2}{4}}=\dfrac{\sqrt{3}l}{2}

So, the area is

\dfrac{AH\cdot HC}{2} = \dfrac{l\cdot\frac{\sqrt{3}l}{2}}{2} = \dfrac{l^2\sqrt{3}}{4} = \dfrac{9\sqrt{3}}{4}

6 0
4 years ago
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