1. Walmart’s stock price started at $70. It went up by $2, then went down by $4. What is the final stock price?

A family is driving from Phoenix to San Francisco. On a map grid, Phoenix is located at (–12, –16), and San Francisco is located

asambeis [7]

The total distance that the family has driven is the sum of the distances from Phoenix to San Francisco,
d = sqrt ((5 - -16)² + (-36 - -12)²) = 10.63
from San Francisco to Blythe,
d = sqrt ((-9 - 5)² + (-20 - -36)²) = 21.26
from Blythe to Los Angeles,
d = sqrt ((-4 - -9)² + (-33 - - 20)²) = 5.83
Adding the distances, we get 37.72.

5 0

2 years ago

Can someone answer this please

Nana76 [90]

Area is trapezium =
A=1/2h(a+b)

84=1/2(6)(7+b)

84=3(7+b)

84=21+3b

3b=84-21

B=63/3

B= 21 cm

I’m sorry if my answer turned out to be wrong but I tried my best so best of luck !!

6 0

2 years ago

Read 2 more answers

PLEASE HELP! EXPLAIN HOW YOU GOT THE ANSWER AND I WILL MARK BRAINLIEST!

kow [346]

3 prefer pop:4 prefer rock
3/4 prefer pop
(3/4)of 14=0.75*14=10.5 people/14people
around 11 people would prefer pop out of 14

7 0

3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

2 years ago

The area (in square feet) of the school sign can be represented by

yawa3891 [41]

Answer:

5x^2+2x-432

Step-by-step explanation:

15x^2+x-215×2+x−2

=15x^2+x-430+x−2

=15x^2+x+x-430-2

=15x^2+2x-432

3 0

1 year ago