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jolli1 [7]
4 years ago
6

HELLPPPP LOTS OF POINTS

Mathematics
2 answers:
kakasveta [241]4 years ago
6 0

Answer:

Her mom and 8/21 needs to be washed.

Step-by-step explanation:


slega [8]4 years ago
4 0

Hi There!

Step-by-step explanation:

Find Common Denominators,

2/7 = 6/21

1/3 = 7/21

Her son washed the most lanudry.

6/21 + 7/21 = 13/21

21/21 - 13/21 = 8/21

Answer:

8/21 of the laundry still needs to be washed.

Hope This Helps :)

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Create two different equations that have infinite solutions to the equations .
Paul [167]

Answer:

1. x = y - 2

2. 2y = 2x

Step-by-step explanation:

1. Any number can fit x and y so long as x is 2 lesser than y and y is 2 more than x.

2. x and y can be any number so long as they are the same number.

6 0
3 years ago
Apply the dilation D to the polygon with the given vertices. Name the coordinates of the image points. Identify and describe the
lukranit [14]

To solve this you just do ehat was done to the coordinates. So x goes from x to 4x do you are mutiplying by 4. and the same goes for y. so your scale factor is 4

 

2 times 4 is 8 and 1 times 4 is four

A(8,4)

4 times 4 is 16 and 1 times four is four

B(16,4)

Four times four is sixteen and negitive three times four is negitive 12

C(16,-12)

 

<span>Given the options the answer will be B. </span>

5 0
3 years ago
Find the area of the circle if r = 5 meters. Leave the answer in terms of π.
olya-2409 [2.1K]

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

4 0
3 years ago
What is the sum of three consecutive odd integers is 75?
tankabanditka [31]
Odd integers are 2 apart
they are n, n+2, n+4

the sum is 75

n+n+2+n+4=75
3n+6=75
minus 6 both sides
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7 0
3 years ago
Give an example of a function f : N → N that is surjective but not injective. You must explain why your example is surjective an
Helen [10]

Answer:

Consider f: N → N defined by f(0)=0 and f(n)=n-1 for all n>0.

Step-by-step explanation:

First we will prove that f is surjective. Let y∈N be any natural number. Define x as the number x=y+1. Then x∈N, and f(x)=x-1=(y+1)-1=y.  We conclude that f is surjective.

However, f is not injective. Take x1=0 and x2=1. Then x1≠x2 but f(x1)=0 and f(x2)=x2-1=1-1=0. We have shown that there are two natural numbers x1,x2 such that x1≠x2 but f(x1)=f(x2), that is, f is not injective.

Note:

If 0∉N in your definition of natural numbers, the same reasoning works with the function f: N → N defined by f(1)=1 and f(n)=n-1 for all n>1. The only difference is that you consider x1=1, x2=2 for the injectivity.

7 0
3 years ago
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