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diamong [38]
3 years ago
13

Danny wants to join the gym. Gym A charges a $20 fee and $40 monthly charges. Gym B charges no joining fee and $45 monthly charg

es. Find the number of months it will take for the total cost for both gyms to be equal
Mathematics
2 answers:
svetoff [14.1K]3 years ago
7 0
It will take 9 months for both gyms to be equal but next month have a small price difference
zlopas [31]3 years ago
4 0

Answer: it will take 4 months for the total cost for both gyms to be equal.

Step-by-step explanation:

Let x represent the number of months it will take for the total cost for both gyms to be equal.

Gym A charges a $20 fee and $40 monthly charges. It means that the cost of using gym A for x months is

40x + 20

Gym B charges no joining fee and $45 monthly charges. It means that the cost of using gym B for x months is

45x

For the cost of both gyms to be the same, the number of months would be

45x = 40x + 20

45x - 40x = 20

5x = 20

x = 20/5

x = 4

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Question 24 Multiple Choice Worth 1 points)
hammer [34]

Given:

The system of equations is:

Line A: y=x-4

Line B: y=3x+4

To find:

The solution of given system of equations.

Solution:

We have,

y=x-4              ...(i)

y=3x+4           ...(ii)

Equating (i) and (ii), we get

x-4=3x+4

-4-4=3x-x

-8=2x

Divide both sides by 2.

-4=x

Substituting x=-4 in (i), we get

y=-4-4

y=-8

The solution of system of equations is (-4,-8).

Now verify the solution by substituting x=-4, y=-8 in the given equations.

-8=-4-4

-8=-8

This statement is true.

Similarly,

-8=3(-4)+4

-8=-12+4

-8=-8

This statement is also true.

Therefore, (-4,-8) is a solution of the given system of equations, because the point satisfies both equations. Hence, the correct option is C.

8 0
2 years ago
The ratio to hearts to moons is | The ratio of moons to all shapes is. I need help due in 10 minutes
Alinara [238K]

Hearts to moon= 6:4

                         = 3:2 (simplified)

Moon to all shapes= 4:10

                               = 2:5 (simplified)

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!! TRIG, Theres a picture!!
BartSMP [9]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

3(  { \tan }^{2} \theta -    { \sec }^{2}  \theta)

Using trigonometric identities

That's

1 + { \tan }^{2} \theta  =   { \sec }^{2}  \theta

Rewrite the expression

That's

3({ \tan }^{2} \theta - (1 + { \tan }^{2} \theta)) \\

Simplify

We have

3({ \tan }^{2} \theta - 1 - { \tan }^{2} \theta) \\ 3({ \tan }^{2} \theta - { \tan }^{2} \theta - 1)

So we have

3( - 1)

We have the final answer as

<h2>- 3</h2>

Hope this helps you

3 0
3 years ago
At the basketball game, Leo scored points in 30% of his attempts. Which of the following statements is true?
Nuetrik [128]

Answer:

C. Leo scored points in 3/10 of his attempts

Step-by-step explanation:

30% is 30/100

Which can simplify to

3/10

5 0
3 years ago
What is the slope of the line tangent to the curve y+2 = (x^2/2) - 2siny at the point (2,0)?
kirza4 [7]
<span>, y+2 = (x^2/2) - 2sin(y) so we are taking the derivative y in respect to x so we have dy/dx use chain rule on y so y' = 2x/2 - 2cos(y)*y'

</span><span>Now rearrange it to solve for y' y' = 2x/2 - 2cos(y)*y' 0 = x - 2cos(y)y' - y' - x = 2cos(y)y' - y' -x = y'(2cos(y) - 1) -x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0 so when f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1) cos(0) = 1 thus f'(2) = -2/(2(1)-1) = -2/-1 = 2 f'(2) = 2
</span>
6 0
3 years ago
Read 2 more answers
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