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netineya [11]
3 years ago
9

298, 209, 129, 58, -4 continue the sequence

Mathematics
1 answer:
anastassius [24]3 years ago
3 0

Answer:-

-93

Step-by-step explanation:

You keep on subtracting 98 from it.

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A public swimming pool that holds 45,000 gallons of water is going to be drained for maintenance at a rate of 100 gallons per mi
crimeas [40]

Answer:

450 minutes

Step-by-step explanation:

Given

w = 45000 - 100t

Required

Determine how long it'll take to empty the pool

Being empty means there's no water in the pool.

So, we have to set w to 0 to get the value of t

i.e w = 0

Substitute 0 for w in w = 45000 - 100t

0 = 45000 - 100t

Collect Like Terms

100t = 45000

Divide through by 100.

t = 450

Hence, it'll take 450 minutes to empty the pool

8 0
3 years ago
Find the slope of the line through the points (0,2) and (5,-3)
andriy [413]
Slope formula is y2-y1/x2-x1.

Using this, we can say that -3 – 2/5 – 0=

1.
8 0
3 years ago
Read 2 more answers
Given the vertex of a quadratic function, find the axis of symmetry.
motikmotik

(i) The equation of the axis of symmetry is x = - 5.

(ii) The coordinates of the vertex of the parabola are (h, k) = (4, - 18). The x-value of the vertex is 4.

(iii) According to the <em>vertex</em> form of the <em>quadratic</em> equation, the parabola opens down due to <em>negative</em> lead coefficient and has a vertex at (2, 4), which is a <em>maximum</em>.  

<h3>How to analyze and interpret quadratic functions</h3>

In this question we must find and infer characteristics from three cases of <em>quadratic</em> equations. (i) In this case we must find a formula of a axis of symmetry based on information about the vertex of the parabola. Such axis passes through the vertex. Hence, the equation of the axis of symmetry is x = - 5.

(ii) We need to transform the <em>quadratic</em> equation into its <em>vertex</em> form to determine the coordinates of the vertex by algebraic handling:

y = x² - 8 · x - 2

y + 18 = x² - 8 · x + 16

y + 18 = (x - 4)²

In a nutshell, the coordinates of the vertex of the parabola are (h, k) = (4, - 18). The x-value of the vertex is 4.

(iii) Now here we must apply a procedure similar to what was in used in part (ii):

y = - 2 · (x² - 4 · x + 2)

y - 4 = - 2 · (x² - 4 · x + 2) - 4

y - 4 = - 2 · (x² - 4 · x + 4)

y - 4 = - 2 · (x - 2)²

According to the <em>vertex</em> form of the <em>quadratic</em> equation, the parabola opens down due to <em>negative</em> lead coefficient and has a vertex at (2, 4), which is a <em>maximum</em>.  

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

5 0
1 year ago
Is the function a polynomial​ function? f(x)=4x-5x^2?
scoundrel [369]
Www.mathcentre.ac.uk/resources/uploaded/mc-ty-polynomial-2009-1.pdf<span>f(x)=4x3. − 3x. 2 + 2 is a polynomial of degree 3, as 3 is the highest power of x in the formula. This is called a cubic polynomial, or just a cubic. 


</span>
7 0
3 years ago
Find the slope line that goes through the following points
grandymaker [24]

Answer:

B and D

Step-by-step explanation:

to calculate the slope m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

(4)

with (x₁, y₁ ) = (0, - 4) and (x₂, y₂ ) = (3, - 1) ← 2 points from table

m = \frac{-1+4}{3-0} = \frac{3}{3} = 1 → B

(5)

with (x₁, y₁ ) = (- 1, - 4) and (x₂, y₂ ) = (2, 5) ← 2 points from table

m = \frac{5+4}{2+1} = \frac{9}{3} = 3 → D


5 0
3 years ago
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