Can some one help pleassse
2 answers:
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Answer: B. H(t) = -6.9(t - 2.3)² + 112
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: y = a(x - h)² + k
where (h, k) is the vertex ⇒ k is the maximum height
the distance traveled is when y = 0 ⇒
Given: H(t) = -7.1(t - 2.3)² + 98
maximum height (k) = 98 feet
distance traveled (x) = = 6.02 seconds
A) H(t) = -7.5(t - 2.2)² + 112
maximum height (k) = 112 feet
distance traveled (x) = = 6.06 seconds
B) H(t) = -6.9(t - 2.3)² + 112
maximum height (k) = 112 feet
distance traveled (x) = = 6.33 seconds
C) H(t) = -6.9(t - 2.4)² + 95
maximum height (k) = 95 feet
This has a lower height than the given equation.
D) H(t) = -7.5(t - 2.3)² + 95
maximum height (k) = 95 feet
This has a lower height than the given equation.
Both options A and B travel higher and stay in the air longer than last year's winner, however option B stays in the air longer than option A.
Answer:
The perimeter of the triangle ABC is 17 cm.
Step-by-step explanation:
Consider the Isosceles triangle ABC.
The sides CA and CB are equal with measures, 5 cm.
The base angles are assumed to be <em>x</em>° each. Hence, the angle ACB is 2<em>x</em>°.
The altitude CP divides the base AB into two equal halves and the angle ACB is also cut into halves.
Consider the right angled triangle ACP.
The sum of all the angles in a triangle is 180°.
Determine the value of <em>x</em> as follows:
<em>x</em>° + <em>x</em>° + 90° = 180°
2<em>x</em>° = 90°
<em>x</em>° = 45°
Compute the length of side AP as follows:
Then the length of side AB is:
AB = AP + PB
= 3.5 + 3.5
= 7 cm
The perimeter of triangle ABC is:
Perimeter = AB + CA + CB
= 7 + 5 + 5
= 17
Thus, the perimeter of the triangle ABC is 17 cm.
