<span>Answer:
The carbons on the closures are sp² hybridized, with a p-orbital for the 'second' bond in the twofold bond with their neighboring carbons.
They have those sp² orbitals covering with the s from the hydrogen, and they have a p covering in the pi bond with the neighboring carbon. They likewise have a sigma bond with the neighboring carbon I'll get to.
The center carbons each have two pi bonds with their neighbors, leaving sp hybridiaztion for the rest. So they have sp/sp² with the end carbons, and sp/sp with each other. (What's more, they likewise have p/p in the pi bonds).
So the total list is:
s/sp²
p/p
sp/sp²
sp/sp</span>
The answer is do it your self you shuld know dis
Change of habitat from a species
Answer:
Welly solved the problem incorrectly. 66 is too small to be a solution to the problem.
Explanation:
sorry if wrong
