As per the the question we need to calculate the value of first 4 multiplied by 10.
Now in the number 4,043, the first 4 is at the thousands place. So the place value of first 4 in the digit 4,043 is 4000.
Multiplying the value of first 4 by 10 we get:
Now, the second 4 in the digit 4,043 is at the tens place. So the place value of second 4 in the digit 4,043 is 40.
We can see that two of them are not equal and the value of first 4 times ten is far greater than the value of second 4.
It can be said that two of the 4s in the digit 4,043 are at two different places, first is at thousands place and second is at tens place. So if the numbers are two places apart their place value will have difference of 100 folds.
Answer: first option.
Step-by-step explanation:
The ratio of the area of the triangles can be calculated as following:
Where is the lenght of the given side of the smaller triangle and is the lenght of the given side of the larger triangle.
Therefore:
It can be written as following:
The ratio of the perimeter is:
Where is the lenght of the given side of the smaller triangle and is the lenght of the given side of the larger triangle.
Therefore:
It can be written as following:
Answer:
1860
Step-by-step explanation:
1875-15 = 1860
Largest 5-digit number is 54312 and is divisible by 6. The smallest 5 digit number is 12,345 and it's not divisible by 6
Let us model this problem with a polynomial function.
Let x = day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.
Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅
Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
| 1 1 1 1 1 | | a₁ | | 42 |
| 2⁴ 2³ 2² 2¹ 2⁰ | | a₂ | | 26 |
| 3⁴ 3³ 3² 3¹ 3⁰ | | a₃ | = | 61 |
| 4⁴ 4³ 4² 4¹ 4⁰ | | a₄ | | 65 |
| 5⁴ 5³ 5² 5¹ 5⁰ | | a₅ | | 56 |
When this matrix equation is solved in the calculator, we obtain
a₁ = 4.1667
a₂ = -55.3333
a₃ = 253.3333
a₄ = -451.1667
a₅ = 291.0000
Test the solution.
y(1) = 42
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56
The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.
Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631