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4 years ago

Invoice Date Terms Date Goods Received June 28 4/8 ROM July 27

Mathematics

1 answer:

S_A_V [24]4 years ago

4 0

Answer:

The answer is "August 4".

Step-by-step explanation:

In the given discount term after receipt of the dates is $\bold{\frac{4}{8}}\\\\$ ROM, which can be defined as follows:

$\Rightarrow 27 \ July + 8 \\\\\Rightarrow 4 \ August$

That's why the final answer is 'August 4'.

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Find the volume of each cylinders. Round your answers to the nearest tenth if necessary. Use 3.14 for T.

wariber [46]

V= πr^2xh

π=3.14
r=6ft
h=8ft

V=3.14x6^2x8=3.14x36x8=904.32ft^3

3 0

3 years ago

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Evgen [1.6K]

Answer:

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3 years ago

A salesman for a shoe company claimed runners would run faster races if they wore the company's brand of running shoe. A track c

gregori [183]

Answer:

Correct option: (c) Paired samples t confidence interval.

Step-by-step explanation:

A paired data is collected from an experiment that is conducted twice; once before applying a treatment and second time after the treatment has been applied.

For example, scores of students before the coaching classes and after the coaching classes.

In this case a paired data is collected.

The runners were asked to run 100-yard wearing their usual shoes one day and do same thing the next day wearing the company's shoes.

The two data collected from both the days is a paired data.

To determine whether the salesman's claim that the runners would run faster races if they wore the company's brand of running shoe is correct or not a confidence interval can be constructed for the paired the data.

If the true mean difference is contained in the interval then the salesman's claim can be considered true otherwise false.

To construct this confidence interval use a paired sample t confidence interval.

Because the population standard deviations are not known.

The (1 - α)% confidence interval for the paired difference is:

$CI=\bar X_{diff}\pm t_{\alpha/2, (n-1)} \frac{\hat \sigma_{diff}}{\sqrt{n}}$

3 0

3 years ago

Suppose that shoe sizes of American women have a bell-shaped distribution with a mean of 8.42 and a standard deviation of 1.52.

Roman55 [17]

Answer:

The percentage of the women have size shoes that are greater than

9.94 is 16%

Step-by-step explanation:

* Lets revise the empirical rule

- The Empirical Rule states that almost all data lies within 3 standard

deviations of the mean for a normal distribution.

- 68% of the data falls within one standard deviation.

- 95% of the data lies within two standard deviations.

- 99.7% of the data lies Within three standard deviations

* The empirical rule shows that

# 68% falls within the first standard deviation (µ ± σ)

# 95% within the first two standard deviations (µ ± 2σ)

# 99.7% within the first three standard deviations (µ ± 3σ).

* Lets solve the problem

- The shoe sizes of American women have a bell-shaped distribution

with a mean of 8.42 and a standard deviation of 1.52

∴ μ = 8.42

- The standard deviation is 1.52

∴ σ = 1.52

- One standard deviation (µ ± σ):

∵ (8.42 - 1.52) = 6.9

∵ (8.42 + 1.52) = 9.94

- Two standard deviations (µ ± 2σ):

∵ (8.42 - 2×1.52) = (8.42 - 3.04) = 5.38

∵ (8.42 + 2×1.52) = (8.42 + 3.04) = 11.46

- Three standard deviations (µ ± 3σ):

∵ (8.42 - 3×1.52) = (8.42 - 4.56) = 3.86

∵ (8.42 + 3×1.52) = (8.42 + 4.56) = 12.98

- We need to find the percent of American women have shoe sizes

that are greater than 9.94

∵ The empirical rule shows that 68% of the distribution lies

within one standard deviation in this case, from 6.9 to 9.94

∵ We need the percentage of greater than 9.94

- That means we need the area under the cure which represents more

than one standard deviation (more than 68%)

∵ The total area of the curve is 100% and the area within one standard

deviation is 68%

∴ The area greater than one standard deviation = (100 - 68)/2 = 16

∴ The percentage of the women have size shoes that are greater

than 9.94 is 16%

8 0

3 years ago

What was their velocity

shutvik [7]

Answer:

Step-by-step explanation:

Wat is the question lol

5 0

3 years ago