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kifflom [539]
3 years ago
5

Write the inverse of g(x) = e x g -1(x) = _____.

Mathematics
1 answer:
mezya [45]3 years ago
6 0

Answer:

g^{-1} (x) = \ln x

Step-by-step explanation:

From the definition if inverse function we can say if y = f(x) and x = h(y) then h(x) is the inverse function of f(x).

Here the given function is g(x) = e^{x} and we have to find the g^{-1} (x) i.e. the inverse function of g(x).

Now, let us assume y = g(x) = e^{x}

Now, taking ln both sides we get, \ln y = \ln e^{x} = x \ln e = x  

{Since \ln e = 1}

⇒ x = \ln y

Therefore, g^{-1} (x) = \ln x (Answer)

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Keiko runs 8 miles in 59 minutes. how many miles does she run per minute?
denis-greek [22]

Answer:

7 Minutes  and 22.5 Seconds Per Mile

Step-by-step explanation:

58/8 = 7.375

Then you have to get the .375 into minutes.

0.375*60 = 22.5


4 0
4 years ago
Read 2 more answers
Which equation has the solutions x = 5+/- 2 the squire root of 7 over 3
coldgirl [10]
If you look at the quadratic formula:

x=(-b±√(b^2-4ac))/(2a)

We can say that -b=5, b=-5

If I read it right you had ±2√7 which is equal to ±√28, and we know b=-5 so:

±√(25-4ac)=±√28

And since 3=2a, a=1.5 making the above:

±√(25-6c)=±√28

25-6c=28

-6c=3

c=-0.5

So a=1.5, b=-5, and c=-0.5 thus 

y=1.5x^2-5x-0.5

We can check this by reapplying the quadratic formula to the equation above

x=(5±√(25-4(1.5)(-0.5))/3

x=(5±√(25+3))/3

x=(5±√28)/3

x=(5±√(4*7))/3

x=(5±2√7)/3
5 0
3 years ago
The steps to derive the quadratic formula are shown below:
insens350 [35]

Answer:

b)

x^{2} +\frac{b}{a} x+(\frac{b}{2 a} )^{2} = \frac{-c}{a} + (\frac{b}{2 a}) ^{2}

Step-by-step explanation:

<u>Step(i)</u>:-

Given quadratic equation ax² + bx + c = 0

<u>step(ii)</u>:-

ax² + bx = -c

<u>Step(iii):</u>-

Dividing 'a' on both sides , we get

\frac{ax^{2} +bx }{a} = \frac{-c}{a}

x^{2} + \frac{bx}{a}  = \frac{-c}{a}

<u><em>Step(iv)</em></u>:-

Adding  (\frac{b}{2 a} )^{2} on both sides , we get

x^{2} +\frac{b}{a} x+(\frac{b}{2 a} )^{2} = \frac{-c}{a} + (\frac{b}{2 a}) ^{2}

8 0
4 years ago
Adjacent angles that form a linear pair are supplementary angles. true or false?
alexandr402 [8]
Ghdghhdyujjhdddbvhfd
5 0
4 years ago
Which of the following is the equation of a line perpendicular to the line y=-3/2x+4, passing through the point (3, 9)?
Anastaziya [24]

Answer: -2x+3y = 21 which is choice C

============================================

Work Shown:

The slope of the original line is -3/2. The perpendicular slope is 2/3. We flip the fraction and flip the sign. Multiplying the original slope (-3/2) and the perpendicular slope (2/3) will result in -1. Let's use this perpendicular slope and the point to find the equation of the perpendicular line in slope intercept form.

y = m+b

y = (2/3)x+b .... plug in the perpendicular slope

9 = (2/3)(3)+b .... plug in the point (x,y) = (3,9)

9 = 2+b

9-2 = 2+b-2 ... subtract 2 from both sides

b = 7

So y = (2/3)x+b turns into y = (2/3)x+7.

This equation is in slope intercept form.

---------------------------

Let's convert to standard form

y = (2/3)x+7

3*y = 3*((2/3)x+7) ... multiply both sides by 3 to clear out the fraction

3*y = 3*(2/3)x+3*7 ... distribute

3y = 2x+21

-2x+3y = 21 .... get the x term to the other side (subtract 2x from both sides)

4 0
3 years ago
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