$\bf \textit{Logarithm Cancellation Rules}
\\\\
log_a a^x = x\qquad \qquad \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{a^{log_a x}=x}
\\\\\\
\textit{logarithm of factors}
\\\\
log_a(xy)\implies log_a(x)+log_a(y)
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
ln(x)+ln(5)=2\implies ln(x\cdot 5)=2\implies log_e(5x)=2
\\\\\\
e^{log_e(5x)}=e^2\implies 5x=e^2\implies x=\cfrac{e^2}{5}$

$\bf \\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
ln(x)-ln(5)=2\implies ln\left( \cfrac{x}{5} \right)=2\implies log_e\left( \cfrac{x}{5} \right)=2\implies e^{log_e\left( \frac{x}{5} \right)}=e^2
\\\\\\
\cfrac{x}{5}=e^2\implies x=5e^2$

5 0

3 years ago

Item Value

7nadin3 [17]

Answer:

TRUE

Step-by-step explanation:

HOPE THIS HELPED!!

7 0

3 years ago

Whats the Answer y=10 4x-5y=3

nikdorinn [45]

4x-5y=3
4x-5(10)=3
4x-50=3
+50 +50
4x=53
/4 /4

x=53/4

6 0

3 years ago

2.5 ( y + ⅖ ) = -13<br> im really bad at math someone pls help

My name is Ann [436]

Answer:

-5.6

Step-by-step explanation:

first distribute the 2.5

also convert the 2/5 to decimal (0.4) because it's hard to work with both decimal and fraction

2.5y + 2.5*0.4 = -13

2.5y +1 = -13

y = -14/2.5 = -5.6

5 0

3 years ago