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Lyrx [107]
3 years ago
15

A contractor is checking the height of the frame for a building his company is constructing. He stands at some distance from the

building and measures the angle of elevation to be 73 degrees. He moves back 10 feet and measures the angle to be 68 degrees. How tall is the building?
Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:

  about 102 feet

Step-by-step explanation:

From the definition of the cotangent function, we can write ...

  h·cot(α1) = d1

  h·cot(α2) = d2

Where h is the building height and (α1, d1), (α2, d2) are (elevation angle, distance from the building) for the two cases.

We have d2 - d1 = 10 ft, so ...

  h(cot(68°) -cot(73°)) = 10 ft

  h = (10 ft)/(cot(68°) -cot(73°)) ≈ (10 ft)/(0.404026 -0.305731) ≈ 101.73 ft

The building is about 102 feet tall.

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AURORKA [14]

Answer:

intervals (-3,-1) and (0,+infinity)

Step-by-step explanation:

if f'(x)>0 then f is increasing

3 0
2 years ago
-4(x+1)+5=17 solve for x
ahrayia [7]

-4(x + 1) + 5 = 17

Distribute -4 inside the parentheses.

(-4x - 4) + 5 = 17

Combine like terms (-4 + 5).

-4x + 1 = 17

Subtract 1 from both sides.

-4x = 16

Divide both sides by -4.

x = -4

3 0
3 years ago
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Given cos A = .25 find angle A in degrees. Round your answer to the nearest hundredth.
Oksana_A [137]
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8 0
3 years ago
Find the obtuse angle between the following pair of straight lines.
ioda

Given:

y=-2

y=\sqrt{3}x-1

To find:

The obtuse angle between the given pair of straight lines.

Solution:

The slope intercept form of a line is

y=mx+b     ...(i)

where, m is slope and b is y-intercept.

The given equations are

y=0x-2

y=\sqrt{3}x-1

On comparing these equations with (i), we get

m_1=0

m_2=\sqrt{3}

Angle between two lines whose slopes are m_1\text{ and }m_2 is

\tan \theta=\left|\dfrac{m_2-m_1}{1+m_1m_2}\right|

Putting m_1=0 and m_2=\sqrt{3}, we get

\tan \theta=\left|\dfrac{\sqrt{3}-0}{1+(0)(\sqrt{3})}\right|

\tan \theta=\left|\dfrac{\sqrt{3}}{1+0}\right|

\tan \theta=\pm \sqrt{3}

Now,

\tan \theta= \sqrt{3} and \tan \theta=-\sqrt{3}

\tan \theta= \tan 60^\circ and \tan \theta=\tan (180^\circ-60^\circ)

\theta= 60^\circ and \theta=120^\circ

120>90, so it is an obtuse angle and 60, so it is an acute angle.

Therefore, the obtuse angle between the given pair of straight lines is 120°.

6 0
3 years ago
657000 in standard form
valkas [14]

6.57000 and in the expontent is how many times u move the decimal up :> hope  i helped

7 0
3 years ago
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