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Lorico [155]
3 years ago
10

The work of a student to find the dimensions of a rectangle of area 8 + 12x and width 4 is shown below:

Mathematics
1 answer:
solmaris [256]3 years ago
7 0

Answer:

Step 2: 4 ( 2 ) + 4 ( 3 x )

Step-by-step explanation:

The student didn't factorise 8 x + 12 properly

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The Yert family hires a landscaping company for 30 weeks. There are two companies to choose from. Green Lawns charges $1 for the
Nikolay [14]

Answer:

$133.77

I am pretty sure that this is the answer.

Step-by-step explanation:

1 + (1.25)^29 = 646.23

200 + (20 x 29) = 780

780 - 646.23 = 133.77

Tell me if I am wrong.

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6 0
3 years ago
Using the chart above, find the total amount and amount of interest paid in the following compound interest problems.
gizmo_the_mogwai [7]

Answer:

Annually: Total Amount = 1611.76, Interest Amount = 711.76

Semiannually: Total Amount = 1625.50 , Interest Amount = 725.50

Quarterly: Total Amount = 1632.62 , Interest Amount = 732.62

Step by Step Explanation:

We can see from the table that the factor that we need to multiply with 900 in order to get amount for compounded annually is 1.7908477. Therefore, our total amount is 1.7908477*900 = 1611.76 and interest earned is 1611.76-900 = 711.76.

The factor that we need to multiply with 900 in order to get amount for compounded semiannually is 1.8061112. Therefore, our total amount is 1.8061112*900 = 1625.50 and interest earned is 1625.50-900 = 725.50.

The factor that we need to multiply with 900 in order to get amount for compounded semiannually is 1.8140184. Therefore, our total amount is 1.8140184*900 = 1632.62 and interest earned is 1632.62-900 = 732.62.

6 0
4 years ago
Can someone help me with this
Kamila [148]

Step-by-step explanation:

please give me brainlest

7 0
3 years ago
Read 2 more answers
The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin
hoa [83]

Answer:

\frac{dI}{dt}=-0.00016 A/s

Step-by-step explanation:

We are given that

By ohm's law

V=IR

R=389 ohm

I=0.03 A

\frac{dV}{dt}=-0.06V/s

\frac{dR}{dt}=0.07ohm/s

We have to find rate of change of current I means \frac{dI}{dt}

Differentiate the equation w.r.t t

\frac{dV}{dt}=\frac{dI}{dt}R+I\frac{dR}{dt}

Substitute the values then we get

-0.06=\frac{dI}{dt}\times 389+0.03\times 0.07

-0.06=389\frac{dI}{dt}+0.0021

-0.06-0.0021=389\frac{dI}{dt}

-0.0621=389\frac{dI}{dt}

\frac{dI}{dt}=\frac{-0.0621}{389}=-0.000160 A/s

Hence, the current I is changing at the rate=-0.00016A/s

4 0
4 years ago
Enter a negative number that is greater than -8
Art [367]

Answer:

-7

Step-by-step explanation:

5 0
3 years ago
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