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goldenfox [79]
3 years ago
10

Use f(x) =1/2 x and f^-1(x)=2x to solve the problems

Mathematics
2 answers:
11111nata11111 [884]3 years ago
6 0

Answer:

F(2)= 1

F^-1(1)= 2

F^-1(f(2))= 2

Step-by-step explanation:

MAXImum [283]3 years ago
4 0
The answer to the question

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-2a+7-3(-9-4a) how do I solve this?
Klio2033 [76]

Answer:

34+4a

Step-by-step explanation:

-2a+7-3(-9-4a)

➡ -2a+7+27+12a

➡34+10a

6 0
3 years ago
A gift bag is shaped like a rectangular prism and has a volume of 1152 cubic inches. The width of the bag is w, the length is 2w
Dafna11 [192]
1. You must use the formula for calculate the volume of a rectangular prism, which is:

 V=(h)(l)(w)

 V: It is the volumen of the rectangular prism (V=1152 inches³).
 h: It is the height of the rectangular prism (h=18-w).
 l:It is the lenght of the rectangular prism (l=2w+4).

 2. When you substitute these calues into the formula, you obtain:

 V=(h)(l)(w)
 1152=(18-w)(2w+4)(w)
 (18-w)(2w+4)(w)-1152=0

 3. Then, you should mutiply them:

 36w²-2w³+72w-4w²-1152=0
 32w²-2w³+72w-1152=0

 4. When you factor, you obtain:

 2(w-16)(w-6)(w+6)

 w1=16
 w2=6
 w3=-6

 5. The problem says that the height is greater than the width, therefore, the widht is:

 w=6 inches

 6. The length is:

 l=2w+4
 l=2(6)+4
 l=16 inches

 7. And the height is:

 h=18-w
 h=18-6
 h=12 inches

 What are the dimensions of the bag?

 The dimensions of the bag are:

 l=16 inches
 h=12 inches
 w=6 inches  
8 0
3 years ago
What is the answer?<br> 2500/x+20<br> =2500/(48.59)+20
sammy [17]
The answer would be 71.45
7 0
3 years ago
1. Emma used elimination to solve this system of linear equations. 3x + 5y = -17 2x + 4y = 6 Which equation did Emma have after
Gwar [14]

Answer:

2y=52

Step-by-step explanation:

1st equation *(-3) and 2nd *(2)

-6x-10y=34

6x+12y=18

eliminate -6x and 6x

add both equations

2y=52

6 0
3 years ago
Read 2 more answers
Answers should be exact decimals (please do not leave as fractions or unfinished calculations).
aksik [14]

Answer:

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)=0.0046

Step-by-step explanation:

a)

As the all outcomes are equally likely, so each number has equal probability of occurring.

For six sided die the sample space is {1,2,3,4,5,6} and each outcome has equal probability of 1/6.

1)

P(rolling the die results in a 3 or a 6)

P(rolling the die results in a 3 or a 6)=P(3)+P(6)=1/6+1/6=2/6=1/3

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)

P(rolling the die results in not getting a 6)=1-P(6)=1-1/6=5/6

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)

number either greater than 2 or less than 5={3,4}

P(rolling the die results in the number being either greater than 2 or less than 5)=2/6=1/3

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)

number is an even number or a 5={2,4,5,6}

P(rolling the die results in an even number or a 5)=4/6=2/3

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)

For six sided die rolled twice the sample space is

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}.

n(S)=6²=36.

rolling the die twice results in a 6 followed by a 4={(6,4)}

P( rolling the die twice results in a 6 followed by a 4)=1/36.

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)

When three die are rolled the number of outcomes=n(S)=6³=216.

rolling the die three times results in all 6's={(6,6,6)}

P(rolling the die three times results in all 6's)=1/216

P(rolling the die three times results in all 6's)=0.0046

Note: All answers are rounded to four decimal places.

8 0
3 years ago
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