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Vikki [24]
3 years ago
10

X is a number from the set [3,5,6] and y is a number from the set [4,7,8,9]. If xz/y is an integer and z is a positive integer,

what is the lowest possible value of z?
A) 1
B) 2
C) 3
D) 4
Plzz help!
Mathematics
1 answer:
UNO [17]3 years ago
4 0

The smallest possible value of z is the denominator of the reduced fraction x/y. We note the prime factors of the members of set y are

... 2², 7, 2³, 3²

so if there are any even members of set x, the fraction can be reduced to something divided by 2. The number 6 in set x is even, so we have

... 6z/4 = 6·2/4 = 3 (an integer) when z=2

The lowest possible value of z is ...

... B) 2

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4 0
3 years ago
Solve x2+10x=24 by completing the square. Which is the solution set of the equation?
AleksandrR [38]
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Final answer: x={-12, 2}
8 0
3 years ago
Read 2 more answers
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