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Oxana [17]
4 years ago
9

A class comprises 26 students. During a mathematics test, one student made 12 mistakes but everyone else in the class made fewer

mistakes than he did. Prove that there were at least 3 students in the class who made the same number of mistakes.​
Mathematics
1 answer:
Rainbow [258]4 years ago
3 0

Answer:

See explanation

Step-by-step explanation:

There are 26 students at the class.

During a mathematics test, one student made 12 mistakes but everyone else in the class made fewer mistakes than he did. So, all other students made 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 or 0 mistakes (12 different possibilites).

Suppose that at most 2 students in the class made the same number of mistakes. Hence, at most 12\cdot 2=24 students satisfy this condition. If we add that student who made 12 mistakes, the maximum total number of students in the class could be

24+1=25 students.

But the total number of students is 26, so our hypothesis is incorrect, thus there are at least 3 students in the class who made the same number of mistakes.​

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They sold 76 t-shirts and 24 warm up pants.

Step-by-step explanation:

Cost of one t-shirt = $20

Cost of warm up pants = $45

Total sold = 100

Worth of sold items = $2600

Let,

x be the number of t-shirts.

y be the number of warm up pants.

According to statement;

x+y=100    Eqn 1

20x+45y=2600   Eqn 2

Multiplying Eqn 1 by 20

20(x+y=100)\\20x+20y=2000\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(20x+45y)-(20x+20y)=2600-2000\\20x+45y-20x-20y=600\\25y=600\\

Dividing both sides by 25

\frac{25y}{25}=\frac{600}{25}\\y=24\\

Putting y=24 in Eqn 1

x+24=100\\x=100-24\\x=76

They sold 76 t-shirts and 24 warm up pants.

Keywords: linear equations, elimination method

Learn more about elimination method at:

  • brainly.com/question/4657040
  • brainly.com/question/4528757

#LearnwithBrainly

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