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VladimirAG [237]
3 years ago
9

Help me with this problem please . Thanks

Mathematics
1 answer:
lesantik [10]3 years ago
3 0
I think the answer is a
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Let {u1,u2,u3} be an orthonormal basis for an inner product space V. If
dybincka [34]

• ||<em>v</em>|| = 42, which is to say

||<em>v</em>||² = 〈<em>v</em>, <em>v </em>〉

…  = 〈<em>a</em> <em>u</em>₁ + <em>b</em> <em>u</em>₂ + <em>c</em> <em>u</em>₃, <em>a</em> <em>u</em>₁ + <em>b</em> <em>u</em>₂ + <em>c</em> <em>u</em>₃〉

… = <em>a</em> ² 〈<em>u</em>₁, <em>u</em>₁〉 + <em>b</em> ² 〈<em>u</em>₂, <em>u</em>₂〉 + <em>c</em> ² 〈<em>u</em>₃, <em>u</em>₃〉 + 2(<em>ab</em> 〈<em>u</em>₁, <em>u</em>₂〉 + <em>ac</em> 〈<em>u</em>₁, <em>u</em>₃〉 + <em>bc</em> 〈<em>u</em>₂, <em>u</em>₃〉)

… = <em>a</em> ² ||<em>u</em>₁||² + <em>b</em> ² ||<em>u</em>₂||² + <em>c</em> ² ||<em>u</em>₃||²

[since each vector in the basis for <em>V</em> is orthogonal to any other vector in the basis, and 〈<em>x</em>, <em>x</em>〉 = ||<em>x</em>||² for any vector <em>x </em>]

42² = <em>a</em> ² + <em>b</em> ² + <em>c</em> ²

[since each vector in the basis has unit length]

42 = √(<em>a</em> ² + <em>b</em> ² + <em>c</em> ²)

• <em>v</em> is orthogonal to <em>u</em>₃, so 〈<em>v</em>, <em>u</em>₃〉 = 0. Expanding <em>v</em> gives the relation

〈<em>v</em>, <em>u</em>₃〉 = 〈<em>a</em> <em>u</em>₁ + <em>b</em> <em>u</em>₂ + <em>c</em> <em>u</em>₃, <em>u</em>₃〉

… = <em>a</em> 〈<em>u</em>₁, <em>u</em>₃〉 + <em>b</em> 〈<em>u</em>₂, <em>u</em>₃〉 + <em>c</em> 〈<em>u</em>₃, <em>u</em>₃〉

… = <em>c</em> ||<em>u</em>₃||²

… = <em>c</em>

which gives <em>c</em> = 0, and so

42 = √(<em>a</em> ² + <em>b</em> ²)

• Lastly, 〈<em>v</em>, <em>u</em>₂〉 = -42, which means

〈<em>v</em>, <em>u</em>₂〉 = 〈<em>a</em> <em>u</em>₁ + <em>b</em> <em>u</em>₂ + <em>c</em> <em>u</em>₃, <em>u</em>₂〉

… = <em>a</em> 〈<em>u</em>₁, <em>u</em>₂〉 + <em>b</em> 〈<em>u</em>₂, <em>u</em>₂〉 + <em>c</em> 〈<em>u</em>₃, <em>u</em>₂〉

… = <em>b </em>||<em>u</em>₂||²

… = <em>b</em>

so that <em>b</em> = -42. Then

42 = √(<em>a</em> ² + (-42)²)   →   <em>a</em> = 0

So we have <em>a</em> = 0, <em>b</em> = -42, and <em>c</em> = 0.

7 0
3 years ago
For constants a ,b, n, R, Van der waals equation relates the pressure P to the volume V of a fixed quantity of a gas at constant
Dahasolnce [82]
Base on your question where a constant A,B,N, R Van der waals equation relates the pressure P to the volume C at fixed quantity of gas at constant value of Temperature T and the ask is to find the rate of change of volume with the pressure dV/dP and the rate of change is 
<span><span>dP/</span><span>dV</span></span>=(<span><span>P+<span><span><span>n2</span>a/</span><span>V2)/(</span></span></span><span>nb−V)</span></span>+<span><span>2<span>n2</span>a/V3</span></span>
3 0
4 years ago
Ellie has 4 liters of punch for the party she needs to measure out servings in milliliters
9966 [12]

Answer:

4 liters = 4000 milliliters

Ellie have 4000 milliliters of punch

Step-by-step explanation:

Given that Ellie has 4 liters of punch and needs to measure out serving in milliliters.

This is a conversion problem, we need to convert;

4 liters to milliliters

1 liter is equivalent to 1000 milliliters

So,

4 liters will be equivalent to 4 × 1000 milliliters.

Therefore;

4 liters = 4000 milliliters

5 0
3 years ago
The product of two whole numbers is 546 and their sum is 47. What are the two numbers
vodka [1.7K]
The two numbers are 26 and 21. HOPE THIS HELPS!
6 0
3 years ago
A company rents cars The company charges a fee of $12 per day plus $0.30 per mile The company also charges $10 per day for insur
Misha Larkins [42]
Everyday the company charges $12 you for renting the car. So, if you rent the car for 7 days then the cost will be $84. $12 * 7 = $84

And for every mile you drive, you pay $0.30. So, if you drive for 100 miles you will pay $30.

Now we can put this into an equation.

y = 12x + 250(0.30)


5 0
3 years ago
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