Question

6x-4y=-15 and x-4y=1

Answer 1

The solution to given system of equations are $(x , y) = ( \frac{-16}{5},\frac{-21}{20})$

Solution:

Given system of equations are:

6x - 4y = -15 ----- eqn 1

x - 4y = 1 -------- eqn 2

We can solve the system of equations by susbtitution method

From eqn 2, solve for varibale "x"

x - 4y = 1

x = 1 + 4y ------- eqn 3

Substitute eqn 3 in eqn 1

6(1 + 4y) - 4y = -15

6 + 24y - 4y = -15

Combine the like terms

6 + 20y = -15

20y = -15 - 6

20y = -21

$y = \frac{-21}{20}$

Substitute the above value of "y" in eqn 3

$x = 1 + 4(\frac{-21}{20})\\\\x = 1 + \frac{-21}{5}\\\\x = \frac{5-21}{5}\\\\x = \frac{-16}{5}$

Thus solution to given system of equations are $(x , y) = ( \frac{-16}{5},\frac{-21}{20})$