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daser333 [38]
3 years ago
8

6x-4y=-15 and x-4y=1

Mathematics
1 answer:
Simora [160]3 years ago
6 0

The solution to given system of equations are (x , y) = ( \frac{-16}{5},\frac{-21}{20})

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

6x - 4y = -15 ----- eqn 1

x - 4y = 1 -------- eqn 2

We can solve the system of equations by susbtitution method

<em><u>From eqn 2, solve for varibale "x"</u></em>

x - 4y = 1

x = 1 + 4y ------- eqn 3

<em><u>Substitute eqn 3 in eqn 1</u></em>

6(1 + 4y) - 4y = -15

6 + 24y - 4y = -15

Combine the like terms

6 + 20y = -15

20y = -15 - 6

20y = -21

y = \frac{-21}{20}

<em><u>Substitute the above value of "y" in eqn 3</u></em>

x = 1 + 4(\frac{-21}{20})\\\\x = 1 + \frac{-21}{5}\\\\x = \frac{5-21}{5}\\\\x = \frac{-16}{5}

Thus solution to given system of equations are (x , y) = ( \frac{-16}{5},\frac{-21}{20})

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