$x^2-6x-5=0\qquad\text{add 5 to both sides}\\\\x^2-6x=5\\\\x^2-2(x)(3)=5\qquad\text{add}\ 3^2\ \text{to both sides}\\\\x^2-2(x)(3)+3^2=5+3^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-3)^2=5+9\\\\(x-3)^2=14\to x-3=\pm\sqrt{14}\qquad\text{add 3 to both sides}\\\\x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}$

8 0

3 years ago

Please Answer i will give brainliest

Firdavs [7]

Answer:

Step-by-step explanation:

It’s c believe me

6 0

3 years ago

Read 2 more answers

PLZZZ HELP ASAP TYSM I NEED THIS ASAP

uysha [10]

Explanation:

See answer for explanation.

Answer:

5x-3+2x=x+7+6x

Answer: There are no solutions.

I'm pretty sure this is correct, sorry if it's not.

Have a lovely evening!

3 0

3 years ago