The correct answer is: [D]: " 3/4" .
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<u> Note</u>: "3/4" = 6/8 = 0.75
"7/8" > "6/8 ;
"3/5" = 6/10 = 0.6 " ; 0.75 > 0.6 ;
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Given:
All the edges of a cube are expanding at a rate of 4 in. per second.
To find:
The rate of change in volume when each edge is 10 in. long.
Solution:
Let a be the edge of the cube.
According to the question, we get


We know that, volume of a cube is

Differentiate with respect to t.


Putting the given values, we get




Therefore, the rate of change in volume 1200 cubic inches per second.
Answer h:
Step-by-step explanation:
Answer:
40 : 43
Step-by-step explanation:
5 : 5 3/8
5: 43/8
lets clear out denominator to eliminate the fraction
(8)(5) : <u>(43)(8)</u><--- the 8's cancel
8 <--- the 8's cancel
40 : 43
40 : 43