Well any number you add can be irrational need more information.
Answer:
64
Step-by-step explanation:
180-52/2=128/2=64
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
Answer:
x - 1
Step-by-step explanation:
We know that, a slant or oblique asymptote of a rational function is the asymptote that helps in determining the direction of the function.
It occurs when the polynomial in the numerator is a higher degree than the polynomial in the denominator.
Now, we divide the numerator by denominator using long division method and the first two terms in the quotient ( forming a linear function ) is the equation of the oblique asymptote.
We are given the rational function, 
.
After dividing we get that, the quotient is x - 1.
Hence, the equation of the oblique asymptote is x-1.
Answer: Side BC has a length of square root 10 units
Step-by-step explanation: I just took the test
