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dlinn [17]
3 years ago
10

The amount of time it takes to finish a race might be a function of which of the following?

Mathematics
2 answers:
Anna11 [10]3 years ago
7 0
The <u>correct answer</u> is:

C) The distance of the race.

Explanation:

If one variable is written as a function of another, this means there is a relationship between the two variables.

There will be a relationship between the time it takes to finish a race and the distance of the race.  The longer the distance of a race is, the more time it will take to finish it.  Therefore the time can be written as a function of the distance.
12345 [234]3 years ago
3 0
The correct answer is C. The distance of the race

The entry fee and the number of people involved can have no influence on the amount of time it takes to finish it.
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Using a system of equations, it is found that the third graph shows a pair of lines that represent the equations with a solution (−5, 2).

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

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More can be learned about a system of equations at brainly.com/question/24342899

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Answer:

9. <em><u>1</u></em><em><u>0</u></em>

10. <em><u>1</u></em><em><u>0</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>

11.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>

12.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>1</u></em><em><u>0</u></em>

Step-by-step explanation:

9.<em><u>U</u></em><em><u>sing </u></em><em><u>Pythagoras</u></em><em><u> Theorem</u></em>

<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>√</u></em><em><u>(</u></em><em><u>H</u></em><em><u>²</u></em><em><u>-</u></em><em><u>B</u></em><em><u>²</u></em><em><u>)</u></em>

<em><u>Where</u></em><em><u>,</u></em>

<em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>perpendicular</u></em><em><u> </u></em>

<em><u>B </u></em><em><u>=</u></em><em><u> </u></em><em><u>Base</u></em>

<em><u>H </u></em><em><u>=</u></em><em><u> </u></em><em><u>Hypotenuse</u></em>

<em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>H</u></em>

<em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u> </u></em><em><u>B/</u></em><em><u>H</u></em>

<em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>B</u></em>

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