Answer:
He owned Cat for 5 years.
Step-by-step explanation:
Given: Owned dog for 9 years.
Dog owned year is one year less than twice as long as he owned a cat.
Lets assume the years that cat has been owned be "x".
Now, finding the number years that Cat hes been owned.
As given, Dog owned year is one year less than twice as long as he owned a cat.
∴ using equation to find the Cat´s owned years.
⇒
adding 1 on both side.
⇒
dividing both side by 2
⇒
∴x=
Hence, Cat has been owned for 5 years.
The only ordered pair that is a solution to the given system of equations is (-2, -6)
<h3>System of Linear Equations </h3>From the question, we are to determine if each ordered pair is a solution to the given system of equations
The given system of equations is
-9x + 2y = 6
5x - 3y = 8
That is,
x = 7, y = 9
Putting the values into the first equation
Is -9(7) + 2(9) = 6
-63 + 18 = 6
-45 ≠ 6
Thus, (7,9) is not a solution
That is,
x = 0, y = 3
Putting the values into the first equation
Is -9(0) + 2(3) = 6
0 + 6 = 6
6 = 6
The ordered pair satisfies the first equation
Testing for the second equation
Is 5(0) - 3(3) = 8
0 - 9 = 8
-9 ≠ 8
Thus, (0, 3) is not a solution
That is,
x = 5, y = -4
Putting the values into the first equation
Is -9(5) + 2(-4) = 6
-45 - 8 = 6
-53 ≠ 6
Thus, (-5,4) is not a solution
That is,
x = -2, y = -6
Putting the values into the first equation
Is -9(-2) + 2(-6) = 6
18 - 12 = 6
6 = 6
The ordered pair satisfies the first equation
Testing for the second equation
Is 5(-2) -3(-6) = 8
-10 + 18 = 8
8 = 8
The ordered pair satisfies the second equation
∴ The ordered pair that is a solution to the system of equations is (-2, -6)
Hence, the only ordered pair that is a solution to the given system of equations is (-2, -6)
Learn more on System of equations here: brainly.com/question/8630769
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<em><u>The expressions that are polynomial are:</u></em>
6 + w
z + 1
<em><u>Solution:</u></em>
A polynomial is an expression with variables and coefficients with the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables
1) 6 + w
Here "w" is a variable, hence it is a polynomial expression
This is a polynomial, since it has variables and coefficients and variable with non negative exponent
3) z + 1
This is also a polynomial with variable "z" and has addition operation
Since it has root so it is not a polynomial