Answer:
4.5m
Step-by-step explanation:
You have to multiply 3 × 1.5= 4.5m
1/2 (12)(5a+7b)
6(5a+7b)
30a + 42b -- I hope this helped
we have
![f(x) =-3x^{2}+ 6x-2](https://tex.z-dn.net/?f=f%28x%29%20%3D-3x%5E%7B2%7D%2B%206x-2)
Since the leading coefficient is negative, the function has a maximum
Let
y=f(x)
![y=-3x^{2}+ 6x-2](https://tex.z-dn.net/?f=y%3D-3x%5E%7B2%7D%2B%206x-2)
Group terms that contain the same variable, and move the constant to the opposite side of the equation
![y+2=-3x^{2}+ 6x](https://tex.z-dn.net/?f=y%2B2%3D-3x%5E%7B2%7D%2B%206x)
Factor the leading coefficient
![y+2=-3(x^{2}-2x)](https://tex.z-dn.net/?f=y%2B2%3D-3%28x%5E%7B2%7D-2x%29)
Complete the square. Remember to balance the equation by adding the same constants to each side
![y+2-3=-3(x^{2}-2x+1)](https://tex.z-dn.net/?f=y%2B2-3%3D-3%28x%5E%7B2%7D-2x%2B1%29)
![y-1=-3(x^{2}-2x+1)](https://tex.z-dn.net/?f=y-1%3D-3%28x%5E%7B2%7D-2x%2B1%29)
Rewrite as perfect squares
![y-1=-3(x-1)^{2}](https://tex.z-dn.net/?f=y-1%3D-3%28x-1%29%5E%7B2%7D)
![y=-3(x-1)^{2}+1](https://tex.z-dn.net/?f=y%3D-3%28x-1%29%5E%7B2%7D%2B1)
the vertex is the point ![(1,1)](https://tex.z-dn.net/?f=%281%2C1%29)
therefore
<u>the answer is the option </u>
A. Maximum at (1, 1)