The probability of rolling a 12 with two dice is 1/36. What is the

2 answers:

6 0

Since the probability of roling 12 is 1/36 we subtract that from how many possibiliies there are and we do this
36/36 (or 1)-1/36=35/36

Alborosie2 years ago

4 0

Because the probability of rolling a 12 is 1/36, what is left over? 35/36. Since 35/36 cannot be simplified, it stays as 35/36. Hope my explanation will inspire you to get better at probability in school. xxx SmileySmartie xxx

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Mekhanik [1.2K]

Answer:

Step-by-step explanation:

Perpendicular lines are lines whose slopes are negative reciprocals of each other

To find the slope of the line we are given, we can rearrange the equation

$4x - 5y = 4\\4x - 4 = 5y\\y = \frac{4}{5}(x) - \frac{4}{5}$

The slope of this line is $\frac{4}{5}$ , so the slope of the other line is $\frac{-5}{4}$

next, we can use the given point to find the equation $y = mx +b$

we know m, we can solve for b

$y = \frac{-5}{4}(x) + b\\-3 = \frac{-5}{4}(-2) + b\\-3 = \frac{5}{2} + b\\\frac{-6}{2} = \frac{5}{2} + b\\$

$b = \frac{-11}{2}$

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2 years ago

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djverab [1.8K]

Quick answer: 0.2908, or %29.0816.

Long answer: So this question is a probability problem, so we take the number we’re looking for and divide it by the whole. Which in this case would be 285/980 Getting us 0.290816326530612 which can be rounded to 0.2908, or in percentage form %29.0816.

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2 years ago

Find the 10th partial sum of the arithmetic sequence defined by

Evgesh-ka [11]

Answer:

22.5

Step-by-step explanation:

If you expand the series, you can see the first few terms of the series:

Putting 1 in $n$ , $\frac{1}{2}(1)-\frac{1}{2}=0$
Putting 2 in $n$ , $\frac{1}{2}(2)-\frac{1}{2}=0.5$
Putting 3 in $n$ , $\frac{1}{2}(3)-\frac{1}{2}=1$
Putting 4 in $n$ , $\frac{1}{2}(4)-\frac{1}{2}=1.5$

We can see the series is 0, 0.5, 1, 1.5, ....

This is an arithmetic series with common difference (the difference in 2 terms) 0.5 and first term 0.

We know formula for sum of arithmetic series:

$s_{n}=\frac{n}{2}(2a+(n-1)d)$

Where,

$S_{n}$ denotes the nth partial sum
$a$ is the first term (in our case it is 0)
$n$ is the term (in our case it is 10 since we want to find 10th partial sum -- sum until first 10 terms)
$d$ is the common difference (difference in term and the previous term) (in our case it is 0.5)