Following the Hardy-Weinberg equilibrium theory, the frequency of the heter0zyg0us genotype is 2pq. In the exposed example, 2pq = 0.48.
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Hardy-Winberg equilibrium</h3>
The Hardy-Weinberg equilibrium theory states that the allelic frequencies in a locus are represented as p and q.
Assuming a diallelic gene,
→ The allelic frequencies are
- p is the frequency of the dominant allele,
- q is the frequency of the recessive allele.
→ The genotypic frequencies after one generation are
- p² (H0m0zyg0us dominant genotypic frequency),
- 2pq (Heter0zyg0us genotypic frequency),
- q² (H0m0zyg0us recessive genotypic frequency).
If a population is in H-W equilibrium, it gets the same allelic and genotypic frequencies generation after generation.
The addition of the allelic frequencies equals 1 ⇒ p + q = 1.
The sum of genotypic frequencies equals 1 ⇒ p² + 2pq + q² = 1
If the allele A has a frequency of 0.6, and the allele B has a frequency of 0.4, then the frequency of the heter0zyg0us genotype is
2pq = 2 x 0.6 x 0.4 =<u> 0.48</u>
You can learn more about the Hardy-Weinberg equilibrium at
brainly.com/question/3406634
Answer:
I think it is A, because the rocks that are at the top are the youngest and the ones that are on the bottom are the oldest.
Explanation:
I think 167 because it takes 1 year for it to grow 3 cm so 500/3 is 167
The requirement was established principally to address the growth of LISTERIA MONOCYTOGENES, which is a bacteria that has the capacity to continue growing even at refrigerated temperatures. The date marking procedure was put in place in order to make sure that the affected foods are discarded before the bacteria can initiate food borne illness.
Eukaryote cells have a nucleus of course , and also you’ll see that its larger and has a cell membrane .
