F(x)=2^x+6
let f(x) = n
f^-1(n) = x
x = 2^n + 6
x - 6 = 2^n
2^n = x - 6
log 2^n = log (x-6)
n log 2 = log (x-6)
n = (x-6)/2
f^-1(x) = (x-6)/2
Answer:
454
Step-by-step explanation:
set up a system of equation
let y be the number of students
let x be the number of adults
because there are twice the amount of students attended as adults, we can use y=2x as one equation
the other equation will be 6.5y+9x=4972 because this represents the total amount of money
plug 2x for y : 6.5(2x)+9x=4972 : x=226
plug 226 in for the first equation : y=2(226) : y=452
Answer:
Step-by-step explanation:
the last choice .. about 3 hours spent on math