Answer:
Output: The question segment gives the following output--
1) 6
2) 5
3) JAVA!
4) i love
5) I LOVEjava!
Explanation:
- "1) 6" comes because "6" is the length of "I LOVE" which is the value of "x" variable and "x.length( )" statement gives the length of the value of "x" variable which is stored on "a" variable and "a" will be printed with "1)" symbol.
- "2) 5" comes because "5" is the length of "java!" which is the value of "y" variable and "y.length( )" statement gives the length of the value of "y" variable which is stored on "b" variable and "b" will be printed with "2)" symbol.
- "3) JAVA! " comes because "JAVA!" is the upper case letter of "java!" which is the value of "y" variable and "y.toUpperCase( )" statement change the value from lower case to uppercase of the value of "y" variable which is stored on "c" variable and "c" will be printed with "3)" symbol.
- "4) i love " comes because "i love" is the lower case letter of "I LOVE" which is the value of "x" variable and "x.toLowerCase( )" statement change the value from uppercase to lowercase of the value of "x" variable which is stored on "d" variable and "d" will be printed with "4)" symbol.
- "5) I LOVEjava! " comes because " I LOVEjava! " is the mixed value of the "x" and "y" variable. It prints because "x.concat(y);" statement combines the x and y value and stored in an "e" variable and "e" will be printed with "5)" symbol.
Answer: no
Your
Explanation: The website says it’s only compatible with Xbox one.
Answer:
it stores the largest value in list (the maximum) in foo
Explanation:
Initially foo is assigned as the first element of the list
Inside the loop, every element in the list will be compared with foo, starting from the second element. If an element is greater than foo, the new value of the foo will be that element. At the end of the loop, foo will be equal to the largest element in the list.
