I don’t really understand what you are trying to ask. Try posting a picture along with your question
Answer:
It's up to personal preference.
Explanation:
iPhone/Apple gives more compliments to security than Android.
Android has more friendly user GUI and dev tools.
Answer:
Giant Tech Company mostly
Explanation:
they used it as their server or storing data, right now example we googling by that we send the requests from our computer to supercomputers and those computer will find that information your and send back the respond (e.g. website Brainly). Supercomputers = computers sample as that.
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
Answer:
First equation x=4
second equation x=3
Explanation:
The question is telling us that 'X' is equal to 8. It's another way of representing this number using X as the variable replacing it.
We input 8 instead of the X to solve the equation, and here in the picture, you can see where I went from there.
Do the same thing for the other equation.
I hope this helps :)
