This is the concept of algebra:
y=^3sqrt(x-5) can be written as:
y=(x-5)^(1/3)
Given that y=0 at the point x=5, that is:
when x=5 then
y=(5-5)^(1/3)
y=0^(1/3)
y=0
from the above we conclude that the domain is:
{x∈ R: x≥5}
That means that the domain is all real numbers greater than or equal to 5.
Answer:
x = -1
Step-by-step explanation:
2x - 7 = 9x
Subtract 2x from both sides: -7 = 7x
Divide both sides by 7: -1 = x
Now plug in 7 for every value of x in the original equation to make sure you are correct:
2(-1) - 7 = 9(-1)
-2 - 7 = -9
-9 = -9
I hope this helps!
Answer:
|60+3c|<2
That should be a less than or equal to sign
Also I’m sorry but I can’t explain it because I got this answer from someone else on here.
Step-by-step explanation:
Answer: x=8/81
Step-by-step explanation
3x divide by 3
8/27 divide by 3
it becomes x=8/27 divide by 3 and 3 becomes 1/3
8/27 x 1/3=8/81
x=8/81
Every week he withdraws $35 from the $950 in his savings, and he wants at least $600 by the end of the summer. So we could write:
Where 'x' is the number of weeks. Now let's solve it for 'x'.
Subtract 950 to both sides:
Divide -35 to both sides, don't forget to switch the sign when dividing/multiplying by a negative number:
So he can only withdraw at money for at most 10 weeks if he wants at least $600 left in his account.