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enyata [817]
3 years ago
11

With or without tiles simplify and solve each equation below for x. record your work. a.3x-7=2

Mathematics
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

<u>x=3</u>

Step-by-step explanation:

Addition property of equality is adding the same number to both sides of an equation does not change the equation.

a+c=b+c

3x-7=2

add 7 both sides of an equation.

3x-7+7=2+7

simplify.

3x=9

divide by 3 both sides of an equation.

3x/3=9/3

simplify.

9/3=3

3*3=9

9/3=3

<u>x=3 and 3=x</u>

Hope this helps!

Thanks!

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Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

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3 years ago
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Answer: the probability is 0.25

Step-by-step explanation:

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The probability that the outcome is an odd number is equal to the number of odd numbers divided the total number of numbers:

p = 5/10 = 0.5

For the second spin the probability is the same, p = 5/10, because the first outcome does not affect the results of the second spin.

The probability of spining an odd number both times, then is the joint probability for two times this same event:

P = (5/10)(5/10) = 0.5*0.5 = 0.25

or 25% in percent form

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