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enyata [817]
3 years ago
11

With or without tiles simplify and solve each equation below for x. record your work. a.3x-7=2

Mathematics
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

<u>x=3</u>

Step-by-step explanation:

Addition property of equality is adding the same number to both sides of an equation does not change the equation.

a+c=b+c

3x-7=2

add 7 both sides of an equation.

3x-7+7=2+7

simplify.

3x=9

divide by 3 both sides of an equation.

3x/3=9/3

simplify.

9/3=3

3*3=9

9/3=3

<u>x=3 and 3=x</u>

Hope this helps!

Thanks!

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7x-6y=9<br> 5x+2y=19 Solve the system using elimination.
ikadub [295]

Step-by-step explanation:

multiply 5x+2y=19 by 3 youll get 15x+6y=57

eliminate y

7x-6y=9

<u>15x+6y=57</u><u> </u> +

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4 0
3 years ago
A) Use the definition of Laplace transform to find L{f }. (Do the integrals.) For what values of s is L{f } defined?f(t) = (2t+1
kiruha [24]

For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

As given in the question,

Given function is equal to :

f(t) = 2t + 1

Simplify the given function using definition of Laplace transform we have,

L(f(t))s = \int\limits^\infty_0 {f(t)e^{-st} } \, dt

          =  \int\limits^\infty_0[2t +1] e^{-st} dt

          = 2\int\limits^\infty_0 te^{-st} + \int\limits^\infty_0e^{-st} dt

         = 2 L(t) + L(1)

L(1) = \int\limits^\infty_0e^{-st} dt

     = (-1/s) ( 0 -1 )

     = 1/s , ( s >  0)

2L ( t ) = 2\int\limits^\infty_0 te^{-st}

        =  2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]

        =  2/ s²

Now ,

L(f(t))s = 2 L(t) + L(1)

          = 2/ s² + 1/s

Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

Learn more about Laplace transform here

brainly.com/question/14487937

#SPJ4

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den301095 [7]
Hello:
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