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telo118 [61]
3 years ago
5

Write the polynomial function, in standard form, that has zeros -1, -2, and 3.

Mathematics
2 answers:
Mandarinka [93]3 years ago
8 0

Answer:

f(x) = x³ - 7x - 6

Step-by-step explanation:

Given that the zeros are x = - 1, x = - 2 and x = 3 then the corresponding factors are

(x + 1), (x +2) and (x - 3)

The polynomial is then the product of the factors, that is

f(x) = (x + 1)(x + 2)(x - 3) ← expand the first pair using FOIL

     = (x² + 3x + 2)(x - 3) ← distribute

     = x³ - 3x² + 3x² - 9x + 2x - 6 ← collect like terms

     = x³ - 7x - 6

Olenka [21]3 years ago
5 0

Answer:

The sum of the roots of a polynomial is 5/3, the product of the same polynomial is -11. Write the polynomial function in standard form.n:

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Suppose you were adding 527+405. What would the tens problem be
nydimaria [60]

it would be 3 because when you add it, it gets to be 932 and the tens place is 3.


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3 years ago
Write the equation of the line in slope intercept form that goes through the point (2,3) and has a slope of -1/2.
elena55 [62]

The answer is y =-1/2x + 3

4 0
4 years ago
Distance between two ships At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (naut
frozen [14]

Answer:

a)\sqrt{144-288t+208t^2} b.) -12knots, 8 knots c) No e)4\sqrt{13}

Step-by-step explanation:

We know that the initial distance between ships A and B was 12 nautical miles. Ship A moves at 12 knots(nautical miles per hour) south. Ship B moves at 8 knots east.

a)

We know that at time t , the ship A has moved 12\dot t (n.m) and ship B has moved 8\dot t (n.m). We also know that the ship A moves closer to the line of the movement of B and that ship B moves further on its line.

Using Pythagorean theorem, we can write the distance s as:

\sqrt{(12-12\dot t)^2 + (8\dot t)^2}\\s=\sqrt{144-288t+144t^2+64t^2}\\s=\sqrt{144-288t+208t^2}

b)

We want to find \frac{ds}{dt} for t=0 and t=1

\sqrt{144-288t+208t^2}|\frac{d}{dt}\\\\\frac{ds}{dt}=\frac{1}{2\sqrt{144-288t+208t^2}}\dot (-288+416t)\\\\\frac{ds}{dt}=\frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\\frac{ds}{dt}(0)=\frac{208\dot 0-144}{\sqrt{144-288\dot 0 + 209\dot 0^2}}=-12knots\\\\\frac{ds}{dt}(1)=\frac{208\dot 1-144}{\sqrt{144-288\dot 1 + 209\dot 1^2}}=8knots

c)

We know that the visibility was 5n.m. We want to see whether the distance s was under 5 miles at any point.

Ships have seen each other = s\leq 5\\\\\sqrt{144-288t+208t^2}\leq 5\\\\144-288t+208t^2\leq 25\\\\199-288t+208t^2\leq 0

Since function f(x)=199-288x+208x^2 is quadratic, concave up and has no real roots, we know that 199-288x+208x^2>0 for every t. So, the ships haven't seen each other.

d)

Attachedis the graph of s(red) and ds/dt(blue). We can see that our results from parts b and c were correct.

e)

Function ds/dt has a horizontal asympote in the first quadrant if

                                                \lim_{t \to \infty} \frac{ds}{dt}

So, lets check this limit:

\lim_{t \to \infty} \frac{ds}{dt}=\lim_{t \to \infty} \frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\=\lim_{t \to \infty} \frac{208-\frac{144}{t}}{\sqrt{\frac{144}{t^2}-\frac{288}{t}+208}}\\\\=\frac{208-0}{\sqrt{0-0+208}}\\\\=\frac{208}{\sqrt{208}}\\\\=4\sqrt{13}

Notice that:

4\sqrt{13}=\sqrt{12^2+5^2}=√(speed of ship A² + speed of ship B²)

5 0
4 years ago
Which graph represents the equation (x-3)^2 + y^2 =16
Goryan [66]

Answer:

C

Step-by-step

Correct on Edge

6 0
3 years ago
Read 2 more answers
If Whitney wrote the decimal representations for the first 300 positive integer multiples of 5 and did not write any other numbe
fiasKO [112]

Answer:

201 times

Step-by-step explanation:

Since it's the first 300 positive integer multiples of 5, then the last integer will be: 300 × 5 = 1500

While the first is 5.

The sequence is like this;

5, 10, 15, 20, 25, 30, 35, .. 1500

Since for every 2 integers that are multiples of 5, 1 will include the digit 5, then it means that, number of times the unit place will have 5 is; 300/5 = 150 times

Now, between 5 and 100, the only value that has 5 in it's tense place is 50 & 55.

So for every 100 numbers, we have 2 times to write 5 in the tens place. Thus, for 1500 numbers, we will write 5 in the tens place: 1500/100 × 2 = 30 times

Now, for the hundreds place, from 500 and 600, we have 21 multiples of 5 inclusive of 500 and 600 but since we want the one that has 5 in the hundreds place, then it is 20 as they all start with 5 excluding 600.

Also, from 1000 to 1500, the only number that has 5 in its hundreds place is 1500.

Thus,total times 5 is written in the hundreds place = 21 times

Total number of times 5 is written = 150 + 30 + 21 = 201 times

5 0
3 years ago
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