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Anestetic [448]
3 years ago
8

Please help me:

Mathematics
1 answer:
Tasya [4]3 years ago
3 0

Answer:

6 units

Step-by-step explanation:

This coordinate is a three dimensional coordinate, which involves positive and negative x,y, and z axis.

The y axis is from left to right, i.e from negative to positive.

So 6 unit left is = -6 but it explains moving left .

Thank you

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A line passes through the points (2,21) and (8,27). Write a linear function rule in terms of x and y for
tatiyna
We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
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2 years ago
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Komok [63]
The rules of exponents tell you to add exponents in the numerator and subtract those in the denominator. A power of a power causes the exponent to be multiplied.

\dfrac{(2x^{3}z^{2})^{3}}{x^{3}y^{4}z^2x^{-4}z^{3}}=2^{3}x^{(3\cdot3-3-(-4))}y^{-4}z^{(2\cdot3-2-3)}\\\\=\dfrac{8x^{10}z}{y^{4}}
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3 years ago
Can someone please help me answer these questions that are attached to the paper and the steps? Thanks in advance!!
Svetach [21]
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3 years ago
Find the area. HELP PLEASE!!!!!!​
kaheart [24]

Answer:

616

Step-by-step explanation:

The equation to find the area of a trapezoid is:  A = ½ (b^1+b²) h.

b1=43

b2=45

h=14

Plug the variables in and solve.

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2 years ago
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Find center,foci, and vertices of ellipse (x+3)^2/21+(y-5)^2/25=1
sasho [114]
I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse. 

(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.) 

\frac{(x-x_{1})^2}{a^2}+ \frac{(y-y_{1})^2}{b^2}=1

Where (x_{1},y_{1}) is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is: 

(-3,5)

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis. 

The major axis in this case is that of the y-axis. In other words, 

b^2>a^2 

So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are: 

(-3,10)
 & (-3,0)

I really hope this helped you! (Partially because I spent a lot of time on this lol) 

Sincerely,

~Cam943, Junior Moderator
6 0
3 years ago
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