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4 years ago

Please help me idk this

Mathematics

1 answer:

Vaselesa [24]4 years ago

5 0

Answer:

5 or more raise the score,

4 or less give it a rest.

9 is in the tenth place. "5 or more raise the score", 9 is more than 5 so you would "raise the score" and the answer would be 1.3. the 2 changes because we are rounding to the nearest tenth.

Hope this helpsssss <3

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Brainliest if correct Solve: 8( 4 - 2^{6} divided by 4)

polet [3.4K]

$\huge\text{Hey there!}$

$\mathsf{\dfrac{8(4 - 2^6)}{4}}$

$\mathsf{2^6}\\\mathsf{\rightarrow2\times2\times2\times2\times2\times2}\\\mathsf{\rightarrow 4\times4\times4}\\\mathsf{\rightarrow 16\times4}\\\mathsf{\rightarrow \bf 64}$

$\mathsf{= \dfrac{8(4 - \bf 64)}{4}}$

$\mathsf{4 - 64}\\\mathsf{\rightarrow \bf -60}$

$\mathsf{= \dfrac{8(\bf -60)}{4}}$

$\mathsf{8(-60)}\\\mathsf{\rightarrow \bf -480}$

$\mathsf{= \dfrac{-480}{4}}\\\\\mathsf{\rightarrow \dfrac{-480\div4}{4\div4}}\\\\\mathsf{\rightarrow- \dfrac{\bf 120}{1}}\\\\\mathsf{\rightarrow \bold{-120}\div 1}}\\\\\mathsf{\rightarrow \bf -120}$

$\huge\text{Therefore, your answer is: \boxed{\mathsf{-120}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

6 0

2 years ago

Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang

Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - α)% confidence interval for the population standard deviation is:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

The information provided is:

n = 26

s = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611$

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

$=\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3$

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0

3 years ago

What is the value of X ?

iogann1982 [59]

I guess you are asking the value of the Angle x, if so
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4 0

3 years ago

What is the length of EF ?

fgiga [73]

Perimeter is the sum of all outside dimensions.

Solve for x first:

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Combine like terms:

4x + 34 = 42

Subtract 34 from both sides:

4x = 8

Divide both sides by 4:

X = 2

Now solve for EF by replacing x:

EF =. X + 7 = 2 + 7 = 9 feet.

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3 years ago

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worty [1.4K]

5 I guess I don't know if it's the right answer

7 0

3 years ago