Answer
c^4-32c^2+256 (Simplified)
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
Answer:
25
Step-by-step explanation:
an absaloute value means that every number inside of that would be a positive number.
we have given that 
where 
represents the number of elements in C.
where we have 4 and 6 which have two elements.
so 
Answer:
I think the answer is 2
Step-by-step explanation:
I it is perpendicular to y=2x-3 then the x value has to be -1 meaning that the x value has to be -2x
so we have Y=-2x+c
We know the Y value is -3 from the co ordinates (0,-3)
so now we have -3=-2x+c
we also know x=0 from the co-ordinates (0,-3)
so we now have -3=-2*0+c
-3=0+c
to make the equation work c has to be -3 meaning that we now have
-3=0-3 which is
Y=-2x-3
