The probability of randomly chosen tall and obese individuals is 0.30.
Firstly complete the given table and find the total of each row and column.
Tall Medium Short Total
Obese 18 28 14 60
Normal 20 51 28 99
Underweight 12 25 9 46
Total 50 104 51 205
We have to find P(Tall | Obese).
P(Tall | Obese) = P(Tall and Obese) / P(Obese)
Now, P(Tall and Obese) = 18 ÷ 205
And, P(Obese) = 60÷205
Substituting the above values,
P(Tall | Obese) = 18÷205/ 60÷205
P(Tall | Obese) = 18/60
P(Tall | Obese) = 0.30
Hence the probability of a tall and obese individual is 0.30.
To learn more about probability, visit: brainly.com/question/11234923
#SPJ9
The answer is 37. 5X5 = 25. 925 divided by 25 is 37
Answer:
si
Step-by-step explanation:
Answer:
The height as a function of time is
h(t) = -(1/2)gt2 + v0t + h0
h(t) = -16t2 + 32t + 20
The ball reaches the ground when h(t) = 0
-16t2 + 32t + 20 = 0
Solve this quadratic equation for t. You will get a positive solution and a negative solution. Discard the negative solution, since time begins at t=0 at the moment the ball is struck. Can you finish from here?
The correct answer is: [A]: "9 (nine) " .
___________________________________________________
<u>Note</u>: We are asked to "enter the degree of the given polynonial". This would be the exponent of the [variable with the HIGHEST EXPONENT VALUE within the polynomial] ; with in this case would refer to: " x ⁹ " ;
→ So; the answer is: "9" {nine.}.
____________________________________________________
