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3 years ago

If y varies directly as x, and y = 25 as x = 5, find y for the x-value 7.

Mathematics

1 answer:

MrRissso [65]3 years ago

3 0

Hope the given solution helps:) Have a great day. Do mark me brainliest if it has really helped you. Thank You.

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A metalworker has a metal alloy that is 15% copper and another alloy that is 75% copper. How many kilograms of each alloy shou

lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51% copper alloy

<em><u>Solution:</u></em>

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51% copper alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

<em><u>Solve the equation for "x"</u></em>

$15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48$

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0

3 years ago

Find the product: −5/3 (−2/3 )(−18)

Dovator [93]

Answer:

A) −20

Step-by-step explanation:

−5/3 (−2/3 )(−18)

Multiply the first and second terms. A negative times a negative is a positive

-5/3 * -2/3 = 10/9

10/9 * -18

Rewriting for easier math

-18/9 * 10

-2 * 10

-20

4 0

3 years ago

Read 2 more answers

Find the area of quadrilateral ABCD. A. 27.28 units² B. 33.08 units² C. 28.53 units² D. 26.47 units²

Ludmilka [50]

Answer:

<h3> $\boxed{ \boxed{ \bold{ \purple{ \sf{28.53 \: {units}^{2} }}}}}$ </h3>

Option C is the correct option.

Step-by-step explanation:

For ABD

$\sf{ = \frac{2.89 + 8.59 + 8.6}{2} }$

$\sf{ = \frac{20.08}{2} }$

$\sf{ = 10.04}$

∆ ABD = $\sf{ = \sqrt{10.04(10.04 - 2.89)(10.04 - 8.59)(10.04 - 8.6)} }$

$\sf{ = \sqrt{10.04 \times 7.15 \times 1.45 \times 1.44 }}$

$\sf{ = \sqrt{149.8891} }$

$\sf{ = 12.2429}$

For ∆ ACD ,

$\sf{s = \frac{8.6 + 4.3 + 7.58}{2} }$

$\sf{ = \frac{20.48}{2} }$

$\sf{ = 10.24}$

∆ ACD = $\sf{ = \sqrt{10.24(10.24 - 8.6)(10.24 - 4.3)(10.24 - 7.58} }$

$\sf{ \sqrt{10.24 \times 1.64 \times 5.94 \times 2.66} }$

$\sf{ = \sqrt{265.3456} }$

$\sf{ = 16.2894}$

Area of quadrilateral ABCD = $\sf{12.2429 + 16.2894}$

$\sf{ = 28.5323}$

$\sf{ = 28.53}$ units ²

Hope I helped!

Best regards!

8 0

3 years ago

Stacey is making candles to sell at the craft fair. She has 5 pounds of wax to make the candles. She needs 18 pound of wax for 1

SIZIF [17.4K]

Answer:

Step-by-step explanation:

To determine how much wax you will need, you will first need to decide on ... (ounces needed) ÷ 16 (ounces in 1 pound) = (pounds of wax needed). For example, let's say you wanted to make 25 candles in our 8 oz Candle Tins ... 5 x 25 = 125 oz of wax ... It's always better to have a little wax left over than to not have enough!

4 0

3 years ago

Simplify: [-5]+2 answer please

drek231 [11]

Answer:

I think it's -3

hope it's right:)

4 0

2 years ago

Read 2 more answers