Question

Metro buses are scheduled to arrive at each stop every 30 minutes. If the time a person waits at a bus stop is uniformly distributed and the maximum possible wait time for a bus is 30 minutes, what is the probability that you will wait more than 25 minutes for a bus

Answer 1

Answer:

The probability is $P(X > 25 ) = 1.667$

Step-by-step explanation:

From the question we are told that

    The  maximum wait is  $b = 30 \ minutes$

      The  minimum wait would be  $a = 0\ minutes$

Generally the probability that you will wait more than 25 minutes for a bus is mathematically represented as

   $P(X > 25 )$

Now given that the time a person waits is uniformly distributed and that the maximum is  30 then we can evaluate the above probability as

    $P(X > 25 ) = P(25 < X < 30 ) = \frac{30 - 25}{30 - 0}$

     $P(X > 25 ) = 1.667$