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mixas84 [53]
3 years ago
15

Graph the relation {(5, 0), (0, 5), (5, 1), (1, 5)}. Is it a function? Why or why not?

Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0

Answer:

No, It does not pass the Vertical-line test.

Step-by-step explanation:

Got this right on gradpoint

MaRussiya [10]3 years ago
4 0
No, it is not a function....for it to be a function, it cant have any repeating x values...they all have to be different....they can have repeating y values, just not the x ones.....also, it does not pass the vertical line test
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Is -27 divided by (-3) positive or negative & how
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Answer:

9

Step-by-step explanation:

-27/-3

27/3 is 9

each of them have a negative so it stays positive

9

7 0
3 years ago
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7 + (10 − 4)to the power 2 ➗ 4 ✖️1 over 2 to the power of 3
iragen [17]

Answer:

86

Step-by-step explanation:

=> 7+(10-4)^2 /4 (\frac{1}{2} )^3

=> 7+(6)^2 / 4(\frac{1}{8})

=> 7+36 / \frac{1}{2}

=> 43 * 2

=> 86

8 0
3 years ago
The sum of six times a number and negative five is negative eleven. Is -1 a reasonable answer?
kupik [55]

Answer:

Yes, -1 is reasonable.

Step-by-step explanation:

Sum means adding +.

(6*-1) - 5 = -11

8 0
3 years ago
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
So far you have mostly worked with equations. There are special types of equations, called functions, that have exactly one outp
EastWind [94]
A calculator (addition) has one and exactly 1 output for every addition problem that you use as an imput
8 0
3 years ago
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