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3 years ago

Graph the relation {(5, 0), (0, 5), (5, 1), (1, 5)}. Is it a function? Why or why not?

Mathematics

2 answers:

julia-pushkina [17]3 years ago

6 0

Answer:

No, It does not pass the Vertical-line test.

Step-by-step explanation:

Got this right on gradpoint

MaRussiya [10]3 years ago

4 0

No, it is not a function....for it to be a function, it cant have any repeating x values...they all have to be different....they can have repeating y values, just not the x ones.....also, it does not pass the vertical line test

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A solenoid has a magnetic field of magnitude 0.50T when carrying a current of 400 A. The solenoid is 8.0 m long. What is the num

mixer [17]

Answer:

The correct answer is "995.22 turns".

Step-by-step explanation:

The given values are:

Magnetic field,

B = 0.50 T

Current,

i = 400 A

Length of solenoid,

L = 8.0 m

As we know,

⇒ $B=\mu_0ni$

then,

⇒ $n=\frac{B}{\mu_0i}$

On substituting the given values, we get

⇒ $=\frac{0.50}{4 \pi\times 10^{-7}\times 400}$

⇒ $=\frac{0.50}{5.024\times 10^{-4}}$

⇒ $=995.22 \ turns$

4 0

3 years ago

Find the number of 4-digit numbers that contain at least three even digits.

mylen [45]

Answer:

2625

Step-by-step explanation:

First let's see all the possible combinations.

(Even=E, Odd= O)

1) EEEO

2) EEOE

3) EOEE

4) OEEE

5) EEEE

Now let's see what E and O possibly could be

E = 0, 2, 4, 5, 6 and 8 (5)

O = 1, 3, 5, 7, 9 (5)

Now we are just simply gonna multiply

1) EEEO = 4*5*5*5

2) EEOE = 4*5*5*5

3) EOEE = 4*5*5*5

4) OEEE = 5*5*5*5

5) EEEE = 4*5*5*5

The even contains a 0, so you can't put 0 in, so (5-1=4), there are only 4 digits for the even.

500 times 4 = 2000

5⁴ = 625

2000+625= 2625

6 0

3 years ago

Consider the quadratic equation x squared = 4x - 5. how many solutions does the equation have?

snow_lady [41]

Answer:

The quadratic equation has two complex solutions

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}=4x-5$

Equate to cero

$x^{2}-4x+5=0$

$a=1\\b=-4\\c=5$

substitute in the formula

$x=\frac{4(+/-)\sqrt{-4^{2}-4(1)(5)}} {2(1)}$

$x=\frac{4(+/-)\sqrt{16-20}} {2}$

$x=\frac{4(+/-)\sqrt{-4}} {2}$

Remember that

$i^{2}=-1$

$x=\frac{4(+/-)2i} {2}$

$x=2(+/-)i$

therefore

The quadratic equation has two complex solutions

5 0

4 years ago

Check all of the values that have three significant figures.

Nadya [2.5K]

A, B, and C are correct

5 0

4 years ago

The mass of the blue copper sulfate crystal is two-thirds the mass of the red fluorite crystal. Write an equation you can use to

Reptile [31]

Answer: multiplication i think

Step-by-step explanation:

3 0

3 years ago

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