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3 years ago

6 16x + 5y = -2 4x - y=-2

Mathematics

1 answer:

Grace [21]3 years ago

5 0

Answer:

x=2/9,y=26/9

Step-by-step explanation:

This is a simultaneous equation

16x+5y=-2..(1)

4x-y=-2...(2)

From (2) make y the subject of formula

y=4x+2..(3)

Substitute (3) into (1)

16x+5(4x+2)=-2

16x+20x+10=-2

36x-10=-2

Add 10 to both sides

36x=8

Divide both sides by 36

x=8/36

Divide both denominator and numerator by 4

x=2/9

Substitute the value x into (3)

y=4(2/9)+2

y=8/9+2

Let the LCM be 9

y=8+18/9

y=26/9

Therefore x=2/9,y=26/9

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A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

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