Answer:
B. a tag
Explanation:
In the structure definition given below:
struct Employee
{
string name;
int idNum;
};
Employee corresponds to the tag of the structure. The tag is used to create additional instances of the structure. For example:
struct Employee e1;
struct Employee e2;
name and idNum are members of the Employee structure and are referenced using the dot notation. e.g.,
struct Employee e1;
e1.idNum=1;
Need further information!!!
The <u>subject </u>line for any e-mail messages you write should clearly state the intention of the e-mail.
Electronic mail (e-mail) is a method of digital communications in which messages are exchanged through the internet. The messages are sent from a sender to one or more receivers. Depending on user’s perspective, every user uses e-mail differently. Communicating via e-mail requires e-mail platforms such as G*mail, Ya*hoo! Mail, Hot*mail, and Out*look etc. In the every e-mail, there is a subject line that clearly state the intention of the e-mail.
Subject line is an important element of an e-mail. Through the subject line, the message written in the e-mail is briefly summarized in six to eight words. A clearly written subject line provides the recipient a clear understanding that why the email has been sent. When recipient replies back to the e-mail, the subject line is changed accordingly.
This is the subject line of the e-mail that convince the receiver whether to open and read the e-mail. So, it should be written in the way that gives clear intention of the e-mail. We can say that the subject line of the e-mail is the most significant few words in the whole e-mail to convey the main purpose of the e-mail.
You can learn more about subject line at
brainly.com/question/14572730
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Answer:
Hard disk drives (HDD), which use one or more rotating discs and rely on magnetic storage, and solid-state drives (SSD), which have no moving mechanical parts, but use flash memory like the kind found in USB flash drives.
Explanation:
Answer:
A is the input array
B = []
; %B is initially an empty array
for i = 1:length(A)/2 %iterates over A until the midpoint of A
B(i) = A(i) + A(end + 1 - i); %This adds the numbers from the first half and %second half of A, and stores in B
end
disp(B)
