Question

Two pools are being filled with water. To start, the first pool had 1850 liters of water and the second pool had 1334 liters of water. Water is being added to the first pool at a rate of 27 liters per minute. Water is being added to the second pool at a rate of 39 liters per minute. (a) For each pool, write an expression for the amount of water in each pool after x months. (b) Write an equation to show when the two pools would have the same amount of water.

Answer 1

Answer:

a)Total amount of water in pool 1 after x minutes = 1850+27x

Total amount of water in pool 2 after x minutes = 1334+39x

b) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39x

Step-by-step explanation:

First Pool :

Initial amount of water in Pool = 1850 liters

Water is being added to the first pool at a rate of 27 liters per minute.

Amount of water added after x minutes = 27x

So, Total amount of water after x minutes = 1850+27x

Second Pool:

Initial amount of water in Pool = 1334 liters

Water is being added to the first pool at a rate of 39 liters per minute.

Amount of water added after x minutes = 39x

So, Total amount of water after x minutes = 1334+39x

Now to find  an equation to show when the two pools would have the same amount of water.

1850+27x= 1334+39x

1850-1334=39x-27x

516=12x

$\frac{516}{12}=x$

43 =x

Hence

a)Total amount of water in pool 1 after x minutes = 1850+27x

Total amount of water in pool 2 after x minutes = 1334+39x

b) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39x