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andriy [413]
4 years ago
7

What is the square root of 12

Mathematics
1 answer:
kodGreya [7K]4 years ago
3 0
Hello! The square root of 12 is 2<span>√<span>3 (</span></span><span>3.46410161 in decimal form)</span><span>. I hope this helps! Don't forget to rate my answer Brainliest ^u^</span>
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Which expression is equivalent to (3x-1) (-5x+6)?
Gnoma [55]

Answer:

−15x2+23x−6

Step-by-step explanation:

(3x−1)(−5x+6)

=(3x+−1)(−5x+6)

=(3x)(−5x)+(3x)(6)+(−1)(−5x)+(−1)(6)

=−15x2+18x+5x−6

=−15x2+23x−6

8 0
3 years ago
Ascending Order<br> 18, 1.8, 18, .018
nexus9112 [7]

Answer:

.018, 1.8, 18, 18

Step-by-step explanation:

ascending means going from smallest to largest, so you order the numbers from smallest to largest

5 0
4 years ago
Which of the following is an arithmetic sequence?–20, –25, –30, –35, –45, ...
timurjin [86]
B) -15.6,-12.9,-10.2,-7.5,-4.8

This is an arithmetic sequence. 
4 0
4 years ago
Read 2 more answers
Find c.
Mazyrski [523]

Answer:

: c2 = a2 + b2 - 2ab cos C

c²=20²+15²-2×15×20×cos50

c²=400+225-600×0.64

c²=241

c=√241=15.5ft

7 0
3 years ago
A ball slides up a frictionless ramp. It is then rolled without slipping and with the same initial velocity up another frictionl
KATRIN_1 [288]

Answer:

Rolling case achieves greater height than sliding case

Step-by-step explanation:

For sliding ball:

- When balls slides up the ramp the kinetic energy is converted to gravitational potential energy.

- We have frictionless ramp, hence no loss due to friction.So the entire kinetic energy is converted into potential energy.

- The ball slides it only has translational kinetic energy as follows:

                                   ΔK.E = ΔP.E

                                   0.5*m*v^2 = m*g*h

                                    h = 0.5v^2 / g

For rolling ball:

- Its the same as the previous case but only difference is that there are two forms of kinetic energy translational and rotational. Thus the energy balance is:

                                  ΔK.E = ΔP.E

                                  0.5*m*v^2 + 0.5*I*w^2 = m*g*h

- Where I: moment of inertia of spherical ball = 2/5 *m*r^2

             w: Angular speed = v / r

                               0.5*m*v^2 + 0.2*m*v^2 = m*g*h

                               0.7v^2 = g*h

                               h = 0.7v^2 / g

- From both results we see that 0.7v^2/g for rolling case is greater than 0.5v^2/g sliding case.

4 0
3 years ago
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