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4 years ago

What is the square root of 12

1 answer:

3 0

Hello! The square root of 12 is 2√3 (3.46410161 in decimal form). I hope this helps! Don't forget to rate my answer Brainliest ^u^

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If a cow has a mass of 9×10^2 kilograms, and a blue whale has a mass of 1.8×10^5 kilograms, which of these statements is true?

bonufazy [111]

$\cfrac{1.8*10^5}{9*10^2}= 0.2*10^3 = 2*10^2=200$

A.The blue whale has about 200 time more mass

6 0

3 years ago

List some words that might be used in a real-world example that can be expressed with an addition problem. (For example: increas

IRISSAK [1]

Answer:

additional

(whatever number) more

consistently increasing

8 0

3 years ago

Jesse deposited $3600 and a new regular savings account earns 6% interest compounded monthly. How much is in the account after o

Sergeu [11.5K]

Answer:

3816

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th

QveST [7]

we know that

the volume of a cone is equal to

$V= \frac{1}{3} \pi r^{2}h$

in this problem

the radius is equal to

$r= \frac{112}{2}= 56ft$

1) Find the height of the cone before the storm

Applying the Pythagorean Theorem find the height

$h^{2} = l^{2}-r^{2}$

$l=65 ft$

$h^{2} = 65^{2}-56^{2}$

$h^{2} = 1,089$

$h=33 ft$

2) Find the volume before the storm

$V= \frac{1}{3}*\pi* 56^{2}*33$

$V=34,496\pi\ ft^{3}$

3) Find the volume after the storm

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

r=(56/3) ft

h=(33/3)=11 ft

$V= \frac{1}{3}*\pi* (56/3)^{2}*11$

$V= 1,277.63\pi\ ft^{3}$

4) Find how this change affect the volume of the pile

Divide the volume after the storm by the volume before the storm

$\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}$

therefore

the answer part a) is

The volume of the pile after the storm is $\frac{1}{27}$ times the original volume

Part b) Estimate the number of lane miles that were covered with salt

5) Find the amount of salt that was used during the storm

$=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}$

6) Find the pounds of road salt used

$104,358.59*80=8,348,687.2\ pounds$

7) Find the number of lane miles that were covered with salt

$8,348,687.2/350=23,853.39 \ lane\ miles$

therefore

the answer part b) is

the number of lane miles that were covered with salt is $23,853.39 \ lane\ miles$

Part c) How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to $1,277.63\pi\ ft^{3}$

$1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}$

8) Find the pounds of road salt

$4,013.79*80=321,103.20\ pounds$

9) Find the number of lane miles

$321,103.20/350=917.44 \ lane\ miles$

therefore

the answer part c) is

the number of lane miles is $917 \ lane\ miles$

7 0

4 years ago

Mr. Menendez ran 13.1 miles at a constant rate for 150 minutes. To find how fast he ran, you solve the equation 13.1 = x • 150.

Novay_Z [31]

X represents his unit rate which is answer #1, speed in miles per minute. It wouldn't make sense to have total distance which is #2 because his total distance is what you are using to find out what x is! Then the number of miles he has run so far makes no sense whatsoever so eliminate that, then 4 is basically is the time it takes to run 13.1 miles which is 150. Hope you understand why the answer is 1. and mark as brainliest!

4 0

4 years ago

Read 2 more answers