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3 years ago

•A ( -3,-4)

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

3 0

Answer:

B.) 10

Step-by-step explanation:

You could use the distance formula to calculate the length of AB, I prefer a visual approach, because it requires less memorization.

Draw a vertical line from B and a horizontal line from A until they intersect at D (5, 4).

Then you have a right triangle ABD, and you can use Pythagoras' theorem to calculate AB.

$\begin{array}{rcl}AB^{2} & = & AD^{2} + BD^{2}\\& = & 8^{2} + 6^{2}\\ & = & 64 + 36\\& = & 100\\AB& = & \sqrt{100}\\&= & \mathbf{10}\\\end{array}$

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Shianne is looking up at the flag on the top of the sailboat she is sailing on. She is sitting 16 feet from the bottom

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Answer:

height of the flag from the bottom of the boat ≈ 32 ft (nearest foot)

Step-by-step explanation:

She is on her boat and the angle of elevation to the top of the flag is 58°. Her eyes her 6 ft above the bottom of the boat she is sailing on. The height of the flag from the bottom of the boat is the sum of the height of the flag and the remaining height from the horizontal line of sight upward to the flag top.

A right angle triangle was formed Shianne line of sight. The angle from her line of sight is 58° from the horizontal. Therefore,

the adjacent side of the triangle formed is 16 ft which is the distance from the boat to the flag.

adjacent side = 16 ft

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using tangential ratio

tan 58° = opposite/adjacent

tan 58° = h/16

cross multiply

h = 16 × 1.60033452904

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3 years ago

Find all the solutions in there interval (0,2pi) for cos5x=-1/2

oee [108]

Answer:

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

Step-by-step explanation:

Solving trigonometric equations.

We are given a condition and we must find all angles who meet it in the provided interval. Our equation is

$cos5x=-\frac{1}{2}$

Solving for 5x:

$5x=\frac{2\pi}{3}+2n\pi$

$5x=\frac{4\pi}{3}+2n\pi$

The values for x will be

$x=\frac{\frac{2\pi}{3}+2n\pi}{5}$

$x=\frac{\frac{4\pi}{3}+2n\pi}{5}$

To find all the solutions, we'll give n values of 0, 1, 2,... until x stops belonging to the interval $(0,2\pi)$

For n=0

$x=\frac{\frac{2\pi}{3}}{5}=\frac{2\pi}{15}$

$x=\frac{\frac{4\pi}{3}}{5}=\frac{4\pi}{15}$

For n=1

$x=\frac{\frac{2\pi}{3}+2\pi}{5}=\frac{8\pi}{15}$

$x=\frac{\frac{4\pi}{3}+2\pi}{5}=\frac{2\pi}{3}$

For n=2

$x=\frac{\frac{2\pi}{3}+4\pi}{5}=\frac{14\pi}{15}$

$x=\frac{\frac{4\pi}{3}+4\pi}{5}=\frac{16\pi}{15}$

For n=3

$x=\frac{\frac{2\pi}{3}+6\pi}{5}=\frac{4\pi}{3}$

$x=\frac{\frac{4\pi}{3}+6\pi}{5}=\frac{22\pi}{15}$

For n=4

$x=\frac{\frac{2\pi}{3}+8\pi}{5}=\frac{26\pi}{15}$

$x=\frac{\frac{4\pi}{3}+8\pi}{5}=\frac{28\pi}{15}$

For n=5 we would find values such as

$x=\frac{\frac{2\pi}{3}+10\pi}{5}=\frac{32\pi}{15}$

$x=\frac{\frac{4\pi}{3}+10\pi}{5}=\frac{34\pi}{15}$

which don't lie in the interval $(0,2\pi)$

The whole set of results is

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

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