Question

Suppose that a population grows according to a logistic model with carrying capacity 6000 and k=0.0015 per year.. Write a logistic differential equation for these data.

Answer 1

♥ thus y’/(yf-y) = k, where yf=6000; 
♠ hence ln(yf-y) =-kx +C; 
at x=0 y(0)=y0=1000, hence C= ln(yf-y0); 
and we get: 
ln((yf-y)/(yf-y0) =-kx; or; 
yf-y =(yf-y0)*exp(-kx); at last 
♦ y = 6000- 5100*exp(-0.0015*x); 

dydt∝y=kyseparate the variablesdyy=kdtintegrate both sides:lny=kt+Cy(t)=Cektby plugging in t=0 we find that C the original populationy(0)=Ce0=C⟹C=y0so we gety=y0ekt