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Sonja [21]
3 years ago
10

Find the common ratio of the geometric sequence 8,2,1/2

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0

Answer:1/4

Step-by-step explanation:

Each term is multiplied by 1/4 to get to the next

Therefore 1/4 is the common ratio

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What is the midpoint of (-7,-9) (6,3)
Advocard [28]

Answer :

Let the first term of both the terms be \:  \sf \: x _1 \:  \: \& \:  \: x _2 and last term be \:  \sf \: y _1 \:  \: \& \:  \: y_2\\

Now, by using the mid point formula to find the mid point of the segment -

\\   \sf \bigg( \frac{x_1 + x_2}{2} , \:  \frac{y_1 + y_2}{2}  \bigg) \\

Now, by substituting the values of both x and y -

\\  \sf \bigg( \frac{ - 7 + 6}{2} , \:   \frac{ - 9 + 3}{2}  \bigg) \\

Adding -7 and 6 -

\\  \sf \bigg( \frac{ - 1}{2} , \frac{ - 9 + 3}{2}  \bigg) \\

Now, move the negative in front of the fraction -

\\  \sf \bigg( \frac{ - 1}{2} , \frac{ - 6}{2}  \bigg) \\  \\  \\  \sf \bigg( \frac{ - 1}{2} , - 3\bigg) \\

6 0
3 years ago
I will give brainliest. <br> What is the hypotenuse and how do I get it?
Ivan

Step-by-step explanation:

by Pythagoras theorem:

perpendicular² + base²= hypotenuse²

(1/√2)²+ (1/√3)² = H²

1/2+1/3= H²

5/6 = H²

√(5/6 )= H

√5/√6 = H

plz mark my answer as brainlist plzzzz.

hope this will be helpful to you

4 0
3 years ago
In Diagram 6, JCK is a tangent to the circle ABC
Igoryamba

Answer:

C

Step-by-step explanation:

if you don't know it choose C

5 0
3 years ago
Divide using synthetic division (3y^4-13y^3+12y^2-33y+9)/(y-4)
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3y³-y²+8y-1+5/y-4. is that unless you want the answer smaller
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3 years ago
Line l is parallel to line e in the figure below.
dexar [7]

Answer:

? need more info

Step-by-step explanation:

6 0
3 years ago
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