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Scorpion4ik [409]
3 years ago
5

Which measurement is a perfect square? the area of a rectangle with a length of 5 and a width of 10 the area of a rectangle with

a length of 5 and a width of 5 the perimeter of a rectangle with a length of 5 and a width of 10 the perimeter of a rectangle with a length of 5 and a width of 5
Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

Answer:

  the area of a rectangle with a length of 5 and a width of 5

Step-by-step explanation:

Area of a rectangle is found by multiplying length and width. When those values are the same, the result is a perfect square.

The area of a rectangle with a length of 5 and a width of 5 is a perfect square.

kow [346]3 years ago
3 0

Answer:

a

Step-by-step explanation:

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3/12% = 25

<em>Therefore, 3 is 12% of 25.</em>

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Ganezh [65]

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I believe its 7?

Step-by-step explanation:

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Write the equation of the line that passes through the points (- 4, - 3) and (3, - 5) . Put your answer in fully reduced slope i
bekas [8.4K]

Answer:

(-4, -3) y (3, -5)  

{-12 y, 15 y}

-12 y + 15 y = 3 y

(3 y)/2

3 sqrt(41) abs(y)

6 0
2 years ago
Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
3 years ago
I need some help with this question
yarga [219]

Answer:

-7/15

Step-by-step explanation:

-4/5 translates to -12/15 and 1/3 translates to 5/15.

When you add -12/15+5/15 you get

-12+5/15 so you get -7/15


5 0
3 years ago
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