Pytagorean theorem
height10
attached at 10-4=6 yards from bottom
8 yards from base to away
a^2+b^2=c^2
a and b are side legnths and c=hypotonuse
so therfore we are given a and b and we must solve for c
so
6=height
8=base
6^2+8^2=c^2
36+64=c^2
100=c^2
square root
10=c
so therfor the legnth of each cable is 10 yards
3 cables so 3 times 10=30
30 yards needed
1.q=p-2n
2.q=75000-2*20000
q=75000-40000
q=35000
3.p=90000+2*25000
p=90000+50000
p=140000
Hope this helps :)
<h3>
Answer: (x² + 1)(x + 1)</h3>
Work Shown:
x³ + x² + x + 1
(x³ + x²) + (x + 1)
x²(x+1) + 1(x + 1)
(x² + 1)(x + 1)
The basic outline is to pair up the terms into two groups. We factor each group separately, and then factor out the overall GCF (x+1). You can use the FOIL rule to verify the answer.
