Help me please guys!!!
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something noteworthy is that the independent and squared variable in this case will be the "x", namely the graph of that quadratic is a vertical parabola.
so the parabola has solutions at x = -2 and x = 4, and its vertex will be half-way between those two guys, namely at x = 1.
since this is a vertical parabola, its axis of symmetry, the line that splits its into twin sides, will be a vertical line, and it'll be the x-coordinate of the vertex, since the vertex hasa a coordinate of x = 1, then the axis of symmetry is the vertical line of x = 1.
Based on the graph given, the option that will show the same amplitude as function m is graph D.
<h3>Which graphed function is this about?</h3>The cosine function is seen as:
f(x) = A*cos(kx) + M
And the functions are:
- A stands for amplitude,
- k is angular frequency,
- M is the midline.
When the function is m(x) = -2*cos(x+π).
The absolute value of the amplitude will be 2*|-2| = 4
Therefore, the option that can have the requirement above is graph D.
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